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4 years ago

6

PLEASE HELP ME I AM TIMED!

2 answers:

iogann1982 [59]4 years ago

6 0

Answer:

The Relative Positions of the sun moon and earth

Explanation:

The moon phase name is shown alongside the image. The dotted line from the earth to the moon represents your line of sight when looking at the moon. ... So the basic explanation is that the lunar phases are created by changing angles (relative positions) of the earth, the moon and the sun, as the moon orbits the earth.

AysviL [449]4 years ago

3 0

The relative positions of the Sun , Moon and Earth

Is the answer I got

Because here's what we know

The earth shadow cast is the common incorrect answer
The earth moves around the sun but the moon has to follow
I don't think the tilt of the earth doesn't have to do with the moon

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a graph compares the weight and height of several different breeds of cat. What type of model is the graph?

pickupchik [31]

Answer: Mathematical Model

Explanation:

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4 years ago

Which of the following determines and objects ability to float in water

AleksandrR [38]

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3 years ago

Characteristics

MAXImum [283]

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4 years ago

What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 du

Crank

<u>Answer:</u>

Work done done by a system on its environment is W=40 Joules

<u>Explanation:</u>

<u>Given:</u>

Ideal gas is maintained at a constant pressure $P=200 \frac{N}{m^{2}}$

Change in Volume $d v= -0.2 m^{3}$

<u>To find:</u>

Work done by a system during an Isobaric Process

<u>Solution:</u>

In a Isobaric Process, constant pressure is maintained, $P=200 \frac{N}{m^{2}}$

According to the formula,

work done $\bold{W=P \times d v}$

Substitute the values of pressure and change in volume in the above formula,

$=200 \times -0.2$

$=40 \text { Joules }$

<u>Result:</u>

Work done done by a system W= -40 Joules

8 0

3 years ago

Read 2 more answers

A fiber-optic rod consists of a central strand of material surrounded by an outer coating. the interior portion of the rod has a

algol13

Answer:

the index of refraction of the coating is 1.33

Explanation:

Given the data in the question;

refraction index of interior portion of the rod η $_{interior$ = 1.55

angle of incidence θ $_i$ = 59.5°

From Snell's law, we know that;

η $_{interior$ × sinθ $_i$ = η $_{coating$ × sinθ $_r$

where η $_{interior$ is the index of refraction of the rod ( material 1 )

θ $_i$ is the angle of incidence

η $_{coating$ is the index of refraction in outer coating ( material 2 )

θ $_r$ is the angle of refraction

so we substitute our values into the equation;

η $_{interior$ × sinθ $_i$ = η $_{coating$ × sinθ $_r$

1.55 × sin( 59.5° ) = η $_{coating$ × sin( 90° )

1.55 × 0.861629 = η $_{coating$ × 1

1.3355 = η $_{coating$ × 1

η $_{coating$ = 1.33 { 2 decimal places }

Therefore, the index of refraction of the coating is 1.33

5 0

3 years ago