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3 years ago

Moishe can ride a bike without giving it any conscious thought moishe ability to ride a bike is an example of—-memory

Physics

2 answers:

s344n2d4d5 [400]3 years ago

8 0

Answer:

Moishe can ride a bike without giving it any conscious thought moishe ability to ride a bike is an example of implicit memory.

Explanation:

The information that you have to consciously remember is explicit memory (for example, the answers to an exam) and the information that you remember unconsciously and effortlessly is known as implicit memory (for example, driving or riding a bicycle). In other words, implicit memory (procedural memory or memory without consciousness) is a type of long-term memory that does not require the intentional recovery of previously acquired experience. This type of memory is unconscious and involuntary. It is also known as non-declarative memory since it is not possible to be aware, it is an automatic memory.

<u><em>Moishe can ride a bike without giving it any conscious thought moishe ability to ride a bike is an example of implicit memory.</em></u>

Anit [1.1K]3 years ago

7 0

Answer:

Implicit

Explanation:

Moishe can ride a bike without giving it any conscious thought moishe ability to ride a bike is an example of implicit memory .

Implicit memory refers to a sort of performing activities with near perfection as a result of numerous previous experiences.

Implicit memory is a demonstration of the learning curve that that says the more you do a thing the easier it becomes to do because you begin to do those things by default or without having to make conscious efforts.

Hence, Moishe's bike riding with unconscious memory is an act of past experiences and of implicit memory.

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A certain digital camera having a lens with focal length 7.50 cmcm focuses on an object 1.70 mm tall that is 4.70 mm from the le

Crank

Answer:

a. 7.62cm

b. Real and inverted

c. 2.76 cm

d. 3450

Explanation:

We proceed as follows;

a. the lens equation that relates the object distance to the image distance with the focal length is given as follows;

1/f = 1/p + 1/q

making q the subject of the formula;

q = pf/p-f

From the question;

p = 4.70m

f = 7.5cm = 0.075m

Substituting these, we have ;

q = (4.7)(0.075)/(4.7-0.075) = 0.3525/4.625 = 0.0762 = 7.62 cm

b. The image is real and inverted since the image distance is positive

c. We want to calculate how tall the image is

Mathematically;

h1 = (q/p)h0

h1 = (7.62/4.70)* 1.7

h1 = 2.76 cm

d. We want to calculate the number of pixels that fit into this image

Mathematically:

n = h1/8 micro meter

n = 2.76cm/8 micro meter = 2.76 * 10^-2/8 * 10^-6 = 3450

3 0

3 years ago

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 29.4 m/s2 m /

Sidana [21]

Answer:

The maximum height is 2881.2 m.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 7.00 s

We need to calculate the distance

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times29.4\times7^2$

$s=720.3\ m$

We need to calculate the velocity

Using formula of velocity

$v=a\times t$

Put the value into the formula

$v=29.4\times7$

$v=205.8\ m/s$

We need to calculate the height

Using formula of height

$H=\dfrac{v^2}{2g}$

Put the value into the formula

$H=\dfrac{(205.8)^2}{2\times9.8}$

$H=2160.9\ m$

We need to calculate the maximum height

Using formula for maximum height

$H'=H+s$

Put the value into the formula

$H'=2160.9+720.3$

$H'=2881.2\ m$

Hence, The maximum height is 2881.2 m.

4 0

3 years ago

What is the longest wavelength in the molecule’s absorption spectrum??

Alisiya [41]

The longest wavelength in the Molecule's absorption spectrum is 2250nm

6 0

2 years ago

Read 2 more answers

When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6

Stella [2.4K]

Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 = +8.4\mu C$

$q_2 = +5.6 \mu C$

force between two charges is given as

$F = 0.66 N$

now we have

$F = \frac{kq_1q_2}{r^2}$

$0.66 = \frac{(9\times 10^9)(8.4 \mu C)(5.6 \mu C)}{r^2}$

$r = 0.8 m$

so it is separated by 80 cm distance

3 0

3 years ago

Read 2 more answers

A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.866 s. How much time

Iteru [2.4K]

<h2>Entire trip takes 1.22 seconds.</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Time, t = 0.866 s

Substituting

s = ut + 0.5 at²

s = 0 x 0.866 + 0.5 x 9.81 x 0.866²

s = 3.68 m

Halfway is 3.68 m

Total height = 2 x 3.68 = 7.36 m

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Time, t = ?

Displacement, s = 7.36 m

Substituting

s = ut + 0.5 at²

7.36 = 0 x t + 0.5 x 9.81 x t²

t = 1.22 s

Entire trip takes 1.22 seconds.

7 0

3 years ago