The internal resistance of ammeter is zero and voltmeter is infinite and, ammeter is connected in series and the voltmeter is in parallel.
To find the answer, we have to study about the internal resistance.
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What is the internal resistance of an ammeter and voltmeter?</h3>
- A circuit has a parallel connection for the voltmeter and a series connection for the ammeter.
- An ammeter is used to calculate the amount of current flowing through a circuit.
- The value of the potential difference or voltage across the load is measured using a voltmeter (resistor).
- The voltage reading on the voltmeter represents the amount of energy that each unit of charge has transmitted to the component.
- An ideal ammeter should have zero internal resistance since it should permit current to flow through it.
- To measure the current flowing through a circuit, an ammeter is connected in series with the circuit.
- Since the internal resistance of the ideal voltmeter should prevent any current from passing through it, it is infinite.
- Voltmeter measures the potential difference, it is connected in parallel.
Thus, we can conclude that, the internal resistance of ammeter is zero and voltmeter is infinite and, ammeter is connected in series and the voltmeter is in parallel.
Learn more about the internal resistance here:
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Answer:
λ = 2 m
f = 100 Hz
Explanation:
When struck in the middle an anti-node is formed at the center, So you can derive,
f = frequency of the fundamental mode in producing standing waves
l = resonating length
T = tension of the wire
m = linear density of the wire
(check the attachment)
By substituting,
f = 100 Hz
Wavelength is twice the vibrating length, its in the section standing waves and using that only the equation is derived.
Imagine what happens when two identical waves in opposite direction superimpose. There will be 3 nodes and two anti-nodes where the distance between two nodes is half the wavelength.
The same case happen here, the transverse sound wave traveling along the wire get reflected by a bridge and bounce back on itself where superposition takes place. So two nodes are at the bridges hence the twice of the distance between bridges is the wavelength of the sound wave.
Hello!
We know that at the BOTTOM of the pendulum's trajectory, the bob has a maximum speed. This means that its KINETIC ENERGY is at a maximum, while its Gravitational POTENTIAL ENERGY is at a minimum.
On the other hand, when the bob is at its highest points, the bob has a velocity of 0 m/s, so its KE is at a minimum and its PE is at a maximum.
We can use the work-energy theorem to solve. Let the Initial Energy equal the bob's energy at one of the sides, while the final Energy equals the bob's energy at the bottom.
Recall that:
PE = mgh
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
KE = 1/2mv²
m = mass (kg)
v = velocity (m/s)
Set the two equal and solve for 'h'.
Cancel mass.
Solve for 'h'.
Answer:
0.0052 m
Explanation:
g = Acceleration due to gravity = 9.78 m/s²
Time period
The length of the pendulum is 0.0052 m