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grandymaker [24]
3 years ago
9

Two more than negative nine times a number is 56. Find the number and write its equation!

Mathematics
1 answer:
taurus [48]3 years ago
3 0

2 + -9n = 56. -9n = 54. N = -6

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HELPPP PLEASEEEEE THANKKKKKSSS
kondor19780726 [428]

The segment to draw is segment UT

Step-by-step explanation:

A line segment is a part of a line that is bounded by two two distinct  end points. In this case, segment UT is bounded by endpoints U and T. In the diagram, point R is not a segment but a point of intersection of segments BT and EU.

Learn More

Construction of a line segment: brainly.com/question/9716065

Keywords : proof, statement, reason, segments, reflexive property

#LearnwithBrainly

6 0
3 years ago
Find the measure of the angle indicated. PLSASE HELP !!!!
Simora [160]

Answer:

Step-by-step explanation:

3x + 4 + 8x + 4 = 140 degree (sum of two interior opposite angle is equal to the exterior angle formed)

11x + 8 = 140

x = 140 - 8

x = 132 /11

x = 12

angle S = 3x + 4

=3*12 + 4

=36 + 4

=40 degree

89 + 5x - 7 = 14x + 1

82 + 5x = 14x + 1

82 - 1 = 14x - 5x

81 = 9x

81/9 = x

9 = x

angle H = 5x - 7

=5*9 - 7

=45 - 7

=38 degree

8 0
3 years ago
Read 2 more answers
Please help me answer this!
Tomtit [17]

Answer:

<em>x = 3</em>

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The ratios of the sides of a right triangle are called trigonometric ratios. The longest side of a right triangle is called the hypotenuse and the other two sides are the legs.

The tangent ratio relates the opposite leg with the adjacent leg. Please note the given side is the opposite leg to 60° and x is the adjacent leg to 60°, thus we apply the tangent ratio:

\displaystyle \tan\theta=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 60^\circ=\frac{3\sqrt{3}}{x}

Solving for x:

\displaystyle x=\frac{3\sqrt{3}}{\tan 60^\circ}

Since:

\tan 60^\circ=\sqrt{3}:

\displaystyle x=\frac{3\sqrt{3}}{\sqrt{3}}

Simplifying:

x = 3

5 0
2 years ago
Using synthetic division, find (x4 − 2) ÷ (x + 1).
Fiesta28 [93]

Answer:

Step-by-step explanation:

We have given:

x^4-2/x+1

Put x+1 = 0

x= 0-1

x= -1

-1 | 1   0   0   0   -2

  |      -1   1   -1     1

_______________

    1    -1   1  -1    -1

Thus it makes the expression:

x^3-x^2+x-1 - 1/x+1

You can further confirm this expression by solving the expression:

(x4 − 2) ÷ (x + 1).

x^4 - 1 -1/x+1

x^4-1/x+1 - 1/x+1

(x^2-1) (x^2+1)/x+1 - 1/x+1

(x-1)(x+1) (x^2+1)/x+1  - 1/x+1

x+1 n the numerator will be cancelled out by x+1 in the denominator.

(x-1) (x^2+1) - 1/x+1

Multiply (x^2+1) by x-1

x(x^2+1) -1(x^2+1)  - 1/x+1

x^3+x-x^2-1 - 1/x+1

x^3-x^2+x-1 - 1/x+1 ....

6 0
3 years ago
F(x)=(4t^2-t) (t^3-8t^2+12) in product rule.<br>​
gavmur [86]

\dfrac{d}{dt} [(4t^2-t)(t^3 -8t^2+12)]\\\\\\=(4t^2-t)\dfrac{d}{dt}(t^3-8t^2 +12) + (t^3 -8t^2 +12) \dfrac{d}{dt} (4t^2 -t)\\\\\\=(4t^2 -t)(3t^2-16t)+(t^3-8t^2+12)(8t-1)\\\\=12t^4-64t^3 -3t^3+16t^2+8t^4-64t^3+96t-t^3+8t^2-12\\\\=20t^4-132t^3+24t^2+96t-12

6 0
2 years ago
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