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sergij07 [2.7K]
4 years ago
14

Which choice is the solution to the inequality below? 2 x < 20

Mathematics
1 answer:
nasty-shy [4]4 years ago
4 0

just divide 20 by coefficient of x

x < 20/2

x < 10

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Graph the line.<br> y=<br> 2<br> -X+3<br> 3
Vesnalui [34]

Answer:

Step-by-step explanation:

4 0
3 years ago
If y:28=5:7, find y​
Ray Of Light [21]

Answer:

y = 20

Step-by-step explanation:

y : 28 = 5 : 7 \\  \\  \frac{y}{28}  =  \frac{5}{7}  \\  \\ y =  \frac{5 \times 28}{7}  \\  \\ y = 5 \times 4 \\  \\ y = 20

3 0
4 years ago
[(15 x 3) + 3] = (12-6) = N​
adelina 88 [10]

Answer:

45+3 = 6=N

48_6= N

42= N

:. N= 42

Step-by-step explanation:

:. N= 42

6 0
3 years ago
Read 2 more answers
Problem 2.
myrzilka [38]

Answer:

a) "An example proves P" False

b) True

c) False

d) True

e) False

f) False

g) True

Step-by-step explanation:

a) If we want to prove P, we have to verify that for all z, P(z) is true. Then, an example is not enough to prove P, it could happen that P(x) is false for some x that is not an example. To elaborate, denote the set of real numbers of R, and define P(z):="z is positive", for z∈R. An example is z=2. However, P(z) is not true in general, a counterexample is z=-1.

If you take P as a proposition, you have to decide the truth value of P, and it must be the same for all possible values of z. In this case, examples and counterexamples can be used sometimes to determine whether P is true or false. We apply this idea below.

b) This is true. Every integer is either even or odd because when you divide by 2, you always get a remainder of 0 (then the integer is even) or 1 (then the integer is odd).

c) This is false. It is not true that every integer is even, a counterexample is the integer 3. Then the proposition "Every integer is even" is false. Similarly, the proposition "Every integer is odd" is false (2 is a counterexample). Both propositions are false, thus the compound proposition is false.

d) This is true. An example is enough: rake r=2. r is rational, and real. Thus some (just one is enough) rational numbers are real.

e) This is false. A counterexample proves this: take z=1+i. z is not imaginary because its real part (1) is not zero. Also, z is not real (i≠0) so not all complex numbers are real or imaginary.

f) False. This would imply that for all real numbers y, y<x. In particular with y=x+1, x+1<x hence 1<0, which is a contradiction.

g) True. Given y∈R, take x=y+1. Then y<x=y+1 as required.

8 0
3 years ago
Researchers randomly divided 500 volunteers into two equal-sized groups. One group spent 6 months on the Paleo diet. A control g
gtnhenbr [62]

Answer:

p_v =P(t_{(498)}>1.356)=0.088

And we can use the following excel code to find it: "=1-T.DIST(1.356,498,TRUE)"

Step-by-step explanation:

Data given and notation

\bar X_{P}=7 represent the mean for the sample Paleo

\bar X_{C}=5 represent the mean for the sample Control

s_{P}=20 represent the sample standard deviation for the sample Paleo

s_{C}=12 represent the sample standard deviation for the sample Control

n_{P}=250 sample size selected Paleo

n_{C}=250 sample size selected Control

\alpha represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the Paleo diet provides more weight control than the control treatment, the system of hypothesis would be:

Null hypothesis:\mu_{P}-\mu_{C}\leq 0

Alternative hypothesis:\mu_{P}-\mu_{C}>0

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{P}-\bar X_{C})-12}{\sqrt{\frac{s^2_{P}}{n_{P}}+\frac{s^2_{C}}{n_{C}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(7-5)-0}{\sqrt{\frac{20^2}{250}+\frac{12^2}{250}}}}=1.356  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{P}+n_{C}-2=250+250-2=498

Since is a one side right test the p value would be:

p_v =P(t_{(498)}>1.356)=0.088

And we can use the following excel code to find it: "=1-T.DIST(1.356,498,TRUE)"

8 0
3 years ago
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