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joja [24]
3 years ago
15

Help asappppp Quickkkkkkkkkkk

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

The answer is C

Step-by-step explanation:

In these questions you have to remember crawl before you walk. So x First then y match up the coordinates (-4,9) and such and the answer should reveal itself.

Regards,

Fellow 8th grader, Abdelmumen Nakoa

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PLZZZZZ HELP ME Find the sum
mario62 [17]

Answer:

27 \frac{2}{3}

Step-by-step explanation:

Ok, so first substitute x for 4 in

"g(x) = 5x + 1", and x for 3 in

"k(x) = 2/x + 2x". Now you got:

g(4) = 5(4) + 1

k(3) = 2/(3) + 2(3)

Now you can solve each individually.

g(4) = 5 × 4 = 20

20 + 1 = 21

g(4) = 21

k(3) = 2 × 3 = 6

6 + 2/3 = 6 2/3

k(3) = 6 2/3

g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>

Hope this helps :)

7 0
2 years ago
Pls help asap
VMariaS [17]

Answer: Addition

Step-by-step explanation: You can represent that as 10^5*10^-5

If you add the exponent values, you get 10^0 which is equal to 1. If you multiply them, you get 10^-25 which is wrong.

3 0
2 years ago
Read 2 more answers
Jacob would like to have $50,000 when he turns 40 (so he can throw a big party for all his former teachers!) he has about 35 yea
zepelin [54]
Jacob must now invest $10,712,72 to have $50,000 for the party.
3 0
3 years ago
What are the coordinates of D’ when the quadrilateral is reflected across the line y = x? On a coordinate plane, quadrilateral A
natita [175]

Answer:

D' (1, 3)

Step-by-step explanation:

When reflected across the y = x line, the "x" and "y" coordinates switch.

If D is (3, 1), then:

x = 3

y = 1

Switch the "x" and "y" values, and rewrite as (x, y).

x = 1

y = 3

D' (1, 3)

7 0
3 years ago
Triangle XYZ has vertices X(–1, –3), Y(0, 0), and Z(1, –3). Malik rotated the triangle 90° clockwise about the origin. What is t
OLga [1]

Answer:

Option D.

Step-by-step explanation:

It is given that triangle XYZ has vertices X(–1, –3), Y(0, 0), and Z(1, –3).

Malik rotated the triangle 90° clockwise about the origin. So, rule of rotation is

(x,y)\to (y,-x)

Now,

X(-1,-3)\to X'(-3,-(-1))=X'(-3,1)

Y(0,0)\to Y'(0,0)

Z(1,-3)\to Z'(-3,-(1))=Z'(-3,-1)

The image points are X’(–3, 1), Y’(0, 0), Z’(–3, –1).

Therefore, the correct option is D.

6 0
3 years ago
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