Answer:
2 grams
Step-by-step explanation:
50 years is 5 half lives as 1 half life is 10 years.
64 divide 2 = 32-1 half life
32 divide 2 =16-2nd half life
16 divide 2 = 8-3rd half life
8 divide 2 = 4-4th half life
4 divide 2 = 2-5th half life
This means we will have 2 grams left of the radioactive substance after 50 years.
Answer:
27 67 16 01 27 35 21 37 74 10
Step-by-step explanation:
Starting from the left, you pick two numbers together and skip two numbers if it is greater than 78.
Meaning:
27816 78416 01822 73521 37741 016312 68000 53645 56644 97892 63408 77919 44575
You pick [27] and leave 81 since it is greater than 78, the population number.
Then you pick [67] and leave 84 as it is also greater than 78.
Then you pick [16] and [01] but leave 82, as it is greater than 78.
Then pick [27], [35], [21], [37], [74] and [10] since they are all less than 78.
At this juncture, you have identified 10 numbers: 27 67 16 01 27 35 21 37 74 10
a to C would be 4 3/4 + 2/3
3/4 + 2/3 = 9/12 + 8/12 = 17/12 = 1 5/12
1 5/12 + 4 = 5 5/12 total distance
Answer:
B. 60L
Step-by-step explanation:
30L = 1hr
2hrs= 30×2= 60L
Answer:
The probability of the temperature exceeding 65 degrees Fahreneit but not needing a rolling blackout is 0.4- Hence, there is a 40% chance.
Step-by-step explanation:
Lets call F the event 'the temperature will exceed 85 degrees Fahrenheit' and B the event 'a blackout will be needed'.
We want P(F ∩ B^c), note that if F happens, there could be 2 disjoint possible events: B or B^c, hence
P(F) = P(F ∩ B) + P(F ∩ B^c)
Hence
P(F ∩ B^c) = P(F) - P(F ∩ B) = 0.6 - 0.2 = 0.4
