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ruslelena [56]
3 years ago
14

Which answer is equivalent to ??? Help please

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

\large\boxed{\dfrac{36}{25}}

Step-by-step explanation:

\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}

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