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Zigmanuir [339]
3 years ago
13

BRAINLIEST AND 100 POINTS! WILL REPORT IF WRONG

Mathematics
1 answer:
Stells [14]3 years ago
4 0

Answer:

You didn't post any choices so attached is the box plot:

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Soo-Jung used the subtraction property of equality to solve an equation for y. Which equation could be the one that Soo-Jung sol
Masteriza [31]

Answer:D y+4=12

Step-by-step explanation:

6 0
3 years ago
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What is 3/4 + 2/3 ???
erica [24]
To add fractions, first convert them to have equal denominators.

3/4= 9/12 (multiply both sides by 3)
2/3= 8/12 (multiply both sides by 4)

From here, add the numerators while keeping the denominator.
9/12+ 8/12= 17/12

Final answer: 17/12 or 1 5/12
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3 years ago
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Find the side of to cube<br> whose volume is<br> 5.832cm3
Scorpion4ik [409]

Answer:

1.8cm

Step-by-step explanation:

Use the volume of cube formula.

\displaystyle V=s^3

\displaystyle5.832=s^3

\displaystyle\sqrt[3]{5.832} =s

\displaystyle s=1.8

3 0
3 years ago
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Wen is factoring the polynomial, which has four terms. 6x3 – 12x2 7x – 14 6x2 (x – 2) 7(x – 2) Which is the completely factored
bonufazy [111]

The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

<h3>What is a factor?</h3>

A factor of n is a number which when multiplied by another number gives us the number n.

In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,

6x^3-12x^2+7x - 14 \\\\

Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as

6x^3-12x^2+7x - 14 \\\\= 6x^2(x-2)+7(x-2)\\\\=(6x^2 +7)(x-2)

Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

Learn more about Factors:

brainly.com/question/6810544

8 0
2 years ago
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The following are the temperatures of 10 days in winter in °C.
lyudmila [28]
The mean is 2.5. also there is mean, median, mode calculators online to help you with these in the future
5 0
2 years ago
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