All categories

2 years ago

Find the quotient 4 / (2/5)=

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

4 0

Answer:

it will be 10

Step-by-step explanation:

You might be interested in

Find the roots of the function g(x) = I4 – 22 – 12.

zepelin [54]

Answer:

-20

Step-by-step explanation:

4 0

2 years ago

For a special sale, a mens tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties and wants to achi

zlopas [31]

Answer:

The average cost of each tie is $56.350

Step-by-step explanation:

We are given that a men tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties

So, Cost of 450 ties = $450 \times 39.99=17995.5$

An order for 100 ties that cost $20.00 each

Cost of 100 ties = $100 \times 20 = 2000$

Total cost price = 17995.5+2000 = 19995.5

Let the selling price of 1 tie be x

Total ties = 450+100 = 550

So, SP of 550 ties =550x

Now we are given that markup is 55%

So, Profit % = 55%

So, $CP = \frac{SP \times 100}{100+P\%}$

Substitute the values

$19995.5 = \frac{550x \times 100}{100+55}$

$19995.5 = \frac{550x \times 100}{155}$

$19995.5 \times 155 = 55000x$

$\frac{19995.5 \times 155}{55000}=x$

$56.350=x$

Hence The average cost of each tie is $56.350

7 0

2 years ago

Help what is greater?45.10 or 45.01???

Anika [276]

45.10 is greater than 45.01

4 0

2 years ago

Read 2 more answers

Find the magnitude of the vector with (-7, -5) and write the vector as the sum of unit vectors.

Lesechka [4]

The magnitude of vector (-7,-5) =
= $\sqrt{ (-7)^{2} + (-5)^{2} } = \sqrt{74} = 8.6$

<span>vector as the sum of unit vectors = -7 i - 5 j</span>

4 0

2 years ago

Read 2 more answers

Use CALCULUS to find coordinates of the turning point on C.

antiseptic1488 [7]

Oi

Just calculating the differential. Step by step:

$y=12 \sqrt{x} -x \frac{3}{2}-10 \\ \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \ \sqrt{x} =x^{ \frac{1}{2} }} \\ \\ Differentiating \\ \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\ \\ y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\ \\ y'=6. \frac{1}{x^{ \frac{1}{2} }} -1. \frac{3}{2} \\ \\ \boxed{y'=\frac{6}{ \sqrt{x} } -\frac{3}{2}}$

If you want to know where the tangent has no slope:

$\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\ \\ \frac{6}{ \sqrt{x} } = \frac{3}{2} \\ \\ 3 \sqrt{x} =12 \\ \\ \sqrt{x} = \frac{12}{3} \\ \\ \sqrt{x} =4 \\ \\ (\sqrt{x})^2 =4^2 \\ \\ x=16$

3 0

2 years ago