Answer:
y+2= -4(x-8)
Step-by-step explanation:
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
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you have to convert meters to centi-meters first;
800m = 80000 cm & 154m = 15400 cm
Now, Substitute that in your original equation;
80035 cm - 15449
64586 cm
(X+1)(x-6) I think is what you’re asking for?
Answer:
The terminal point is (1, 0) ⇒ D
Step-by-step explanation:
In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis.
- The terminal point on the positive part of the x-axis is (1, 0),which means Ф = 0° or 360° and cosФ = 1, sinФ = 0
- The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
- The terminal point on the negative part of the x-axis is (-1, 0),which means Ф = 180° and cosФ = -1, sinФ = 0
- The terminal point on the negative part of the y-axis is (0, -1),which means Ф = 270° and cosФ = 0, sinФ = -1
In a unit circle
∵ Ф = 2π radians
∵ 2π radians = 360°
→ By using the 1st rule above
∴ The terminal point is (1, 0)
