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castortr0y [4]
3 years ago
14

Help pls I’m #######} my teacher gave this to me without knowing nun

Mathematics
1 answer:
butalik [34]3 years ago
7 0

Basically, you just move every individual point up, down, left, or right by the amount indicated.

For example, point G is graphed on the point (-3, -1). Moving it right 5 and up 1 will give you G’, which is (2,0)

T is graphed on the point (-1, -1). Moving it right 5 and up 1 will give you T’, which is (4,0)

B is graphed on the point (-3, -5). Moving it right 5 and up 1 will give you B’, which is

(2,4)

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I WILL GIVE BRAINLY
Akimi4 [234]

Answer:

3/11 or 0.27777777777

Step-by-step explanation:

7 0
4 years ago
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In a study, 42% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people
kobusy [5.1K]

Answer:

The probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of adults questioned reported that their health was excellent.

A random sample of <em>n</em> = 11 adults are selected randomly selected from an area a nuclear power plant.

Of these 11 adults <em>X</em> = 3 reported that their health was excellent.

The proportion of adults who reported that their health was excellent is:

p=\frac{X}{n}=\frac{3}{11}

An adult's health condition is not affected by others, i.e. they are independent.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 11 and <em>p</em> = \frac{3}{11}.

The probability mass function of <em>X</em> is:

P(X=x)={11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x};\ x=0,1,2,3...

Compute the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health as follows:

P (X ≤ 3) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

              =\sum\limits^{3}_{x=0}{{11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x}}\\=0.02998+0.12385+0.23254+0.26197\\=0.64834\\\approx 0.6483

Thus, the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

5 0
3 years ago
Geometry! Please help with math!
Angelina_Jolie [31]
I am not for sure how to do this just yet when I figher it out I will try to help you.<span />
7 0
4 years ago
I’n the Miller family there are 8 boys and 12 girls what is the ratio of boys to girls ?
Rina8888 [55]

Answer:

4:6

Step-by-step explanation:

because 2 is common factor of 8 and 12 so 8 divided by 2 equal 4 and 12 divided by 2 equals 6

6 0
3 years ago
Jazz and Catherine can eat 50 pounds bag of peanuts in 30 days jazz himself it's 50 pounds of peanuts two weeks last time then C
Cerrena [4.2K]

Answer:

  67.8 days

Step-by-step explanation:

We assume the problem statement is supposed to read ...

Jazz and Corbin can eat 50 pounds of peanuts in 30 days. Jazz by himself eats 50 pounds of peanuts in two weeks less time than Corbin does by himself. How many days will it take for Corbin to eat the 50 pounds of peanuts by himself?

__

Let c represent the number of days it takes Corbin to eat 50 lbs of peanuts. Then c - 14 will be the number of days it takes Jazz to eat 50 lbs of peanuts. Working together, they eat 50 lbs of peanuts in 30 days, so ...

  Jazz's peanuts per day + Corbin's peanuts per day = total peanuts per day

  50/c + 50/(c-14) = 50/30

Multiplying by (3/5)c(c-14), we get ...

  30(c -14) + 30c = c(c -14)

Subtracting the left side gives ...

  c^2 -14c -60c +420 = 0

  c^2 -74c +1369 = 1369 -420 . . . . subtract 420, add 1369 to complete the square

  (c -37)^2 = 949 . . . . . . . . . write more compactly

  c = 37 +√949 ≈ 67.8 . . . . square root and add 37

It will take 67.8 days for Corbin to eat 50 lbs of peanuts by himself.

5 0
3 years ago
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