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3 years ago

Help pls I’m #######} my teacher gave this to me without knowing nun

Mathematics

1 answer:

butalik [34]3 years ago

7 0

Basically, you just move every individual point up, down, left, or right by the amount indicated.

For example, point G is graphed on the point (-3, -1). Moving it right 5 and up 1 will give you G’, which is (2,0)

T is graphed on the point (-1, -1). Moving it right 5 and up 1 will give you T’, which is (4,0)

B is graphed on the point (-3, -5). Moving it right 5 and up 1 will give you B’, which is

(2,4)

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kevin has $42 and is saving $8 per week. how many weeks must kevin save in order to have 138 altogether

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Answer:

1 year and 5 months

Step-by-step explanation:

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3 years ago

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Using the diagram below, translate the figure 3 units to the left and 2 units up. Graph the translated figure and provide the tr

aleksandrvk [35]

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3 years ago

Find the value of x then classify the triangle

butalik [34]

3.)

180-90-59=x
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4.)

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

A two-factor research study has 2 levels of factor A and 3 levels of factor B with a separate sample of n = 5 subjects in each t

amid [387]

Answer:

option (b) df = 1, 24

Step-by-step explanation:

Data provided in the question:

levels of factor A, a = 2

levels of factor B, b = 3

Subjects in each Sample, s = 5

n = 5 × 3 × 2 = 30

Now

df for Factor A = a - 1

= 2 - 1

= 1

df for Factor B = b - 1

= 3 - 1

= 2

df for Interaction AB = ( a - 1 ) × ( b - 1 )

= 1 × 2

= 2

df for Total = n - 1

= 30 - 1

= 29

df for error = 29 - 5

= 24

Hence,

df values for the F-ratio evaluating the main effect of factor A is 1, 24

The correct answer is option (b) df = 1, 24

6 0

4 years ago