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2 years ago

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Mathematics

1 answer:

Ne4ueva [31]2 years ago

3 0

-5x+4y-7x-9y
-12x-5y
12x+5y=I

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A borrower had a loan of $ 60 comma 000.00 at 4 % compounded annually comma with 8 annual payments. Suppose the borrower paid of

quester [9]

Answer:

The amount needed to pay off the loan after 4 years is $70,192

Step-by-step explanation:

When interest is compounded annually, total amount A after t years is given by:

$A = P(1 + r)^{t}$

where P is the initial amount (principal), r is the rate and t is time in years.

From the question:

P = $60,000

r = 4% = 0.04

t = 4

$A = 60000(1 + 0.04)^{4} \\A = 60000(1.04)^{4}\\A = 60000 * 1.16985856\\A = 70191.5136\\A = 70192$

The amount needed to pay off the loan after 4 years is $70,192

If we divide the amount by four, we will get the amount that is paid yearly (70192/4 = 17548). $17,548 is paid yearly.

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2 years ago

Aiden has a loyalty card good for a 20% discount at his local grocery store. What would his total in dollars and cents be, after

JulsSmile [24]

Answer:

$20.60

Step-by-step explanation:

25.75x20%=5.15

25.75-5.15=20.60

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2 years ago

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Please help with this

zysi [14]

Crayon and then marker

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2 years ago

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Prove the divisibility:<br><br>45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

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2 years ago

Where is the highest population denisty in the eastern United States?

Leviafan [203]

Answer:

North east

Step-by-step explanation:

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2 years ago