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2 years ago

Solve the inequality. 5q + 22-13

Mathematics

1 answer:

kirill115 [55]2 years ago

6 0

Answer:

The answer is 5q + 9.

Step-by-step explanation:

1) Collect like terms.

$5q + (22 - 13)$

2) Simplify.

$5q + 9$

hence, the answer is 5q + 9.

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Need one person help for math Plato class

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2 years ago

Which function represents the quadratic function f(x) = x^2 after a vertical stretch by a factor of number 2?

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2 years ago

Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat

NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that $n = 65, \pi = 0.76$

99% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964$

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

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2 years ago

Hawick is 1515 miles south of Abbotsford, and Kelso is 1717 miles east of Abbotsford. What is the distance from Hawick to Kelso?

Mashcka [7]

Answer:

As per the statement:

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

Let H represents Hawick , A represents Abbotsford and K represents Kelso

See the diagram as shown below:

Distance of AH = 15 miles

Distance of AK = 17 miles.

We have to find the distance HK:

Using Pythagoras theorem;

$\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2$

then;

$\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514$

$HK = \sqrt{514} =22.671581$ miles.

Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles

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3 years ago

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3 years ago