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gayaneshka [121]
3 years ago
14

Solve the inequality. 5q + 22-13

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

The answer is 5q + 9.

Step-by-step explanation:

1) Collect like terms.

5q + (22 - 13)

2) Simplify.

5q + 9

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>5q</u><u> </u><u>+</u><u> </u><u>9</u><u>.</u>

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Hi does anyone know what m+20=6, please show work with it
erik [133]
So your equation is m + 20 = 6

The first think you do is subtract 20 from both sides in order to get “m” alone, since that’s the variable you’re solving for. So what you’ll you have next is
m + 20 - 20 = 6-20

Since 20 subtracted by itself is zero, you’ll be left with
m + 0 = -14

Or more simply

m = -14
8 0
3 years ago
Solve please help<br> What's the answer
Nady [450]
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4 0
4 years ago
Read 2 more answers
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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The coordinates of the fourth corner is A. (-1, 3)

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Step-by-step explanation:

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