The forces result in a right triangle. To obtain the resultant force, one can simply use the Pythagorean theorem. 1250 lbf and 2650 lbf both act as the legs of the triangle. Obtaining the hypotenuse via the theorem would yield the resultant force. This is done below:
c^2 = a^2 + b^2
c^2 = (1250)^2 + (2650)^2
c = 2930.017 lbf
Therefore, the magnitude of the resultant force is approximately equal to 2930 lbf.
C) m∠5 + m∠6 =180°
D) m∠2 + m∠3 = m∠6
E) m∠2 + m∠3 + m∠5 = 180°
Step-by-step explanation:
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Answer:
Please let me know if your quadratic is 
.
And if so your vertex is (-2,2) and your y-intercept is (0,-6)
Step-by-step explanation:
It says vertex so I'm thinking you meant . Please correct me if I'm wrong.
The vertex form of a quadratic is 
. It is called that because it tells you the vertex (h,k).
So if you compare the two forms you should see -h=2 while k=2.
-h=2 implies h=-2.
So the vertex is (h,k)=(-2,2).
To find the y-intercept, set x=0 and find y.
So the y-intercept is (0,-6).
2n + 1
the number before n is the difference (what it goes up in), and the second is the ‘zeroth’ term: you take away the 2 you got from the first value, 3, and get 1 :)
<h3>Answer: RS = 16</h3>
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Explanation:
The ratio QR : RS : ST is equal to 1 : 4 : 5
This means we have the following three equations
For some positive number x.
Note the ratio QR : RS : ST turns into x : 4x : 5x, which reduces to 1 : 4 : 5 when we divide all three parts by x
.
Along with those three equations, we'll also use QT = 40 as well.
Now turn to the segment addition postulate. Plug in the equations mentioned earlier, and solve for x
.
QT = QR + RS + ST
40 = x+4x+5x
40 = 10x
10x = 40
x = 40/10
x = 4
So we know that
QR = x = 4
RS = 4x = 4*4 = 16
ST = 5x = 5*4 = 20
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As a check,
QR + RS + ST = 4 + 16 + 20 = 40
which is the same as QT = 40
Therefore, we've confirmed that QR + RS + ST = QT is correct and we've confirmed our answers.
