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scoundrel [369]
3 years ago
10

Simplify: 3x + 6y - (4x - 2y)

Mathematics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

-x + 8y

Step-by-step explanation:

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Which relationship describes angles 1 and 2?
tamaranim1 [39]
Angles 1 and 2 are adjacent, we know this because they are side by side. Meaning they are adjacent.

Angles 1 and 2 are also complementary because they add up to 90°
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A farm lets you pick 3 pints of raspberries for 12.00 what is the price per pint/
BaLLatris [955]

Answer:

$4

Step-by-step explanation:

I tried to make it as simple as possible.

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As a sales person, you are paid $100 per week plus a commission of $5 per sale. If you want to earn at least $275 this week, how
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275-100=175 (amount of bonus) 175÷5 (amount per bonus)= 35 total sales
8 0
3 years ago
Solve the quadratic equation by completing the square.<br> x²–2x-12=0
inn [45]

Answer:

(x-1)^2-13=0

x = \sqrt{13}+1

Step-by-step explanation:

Completing the square is a method of rewriting a quadratic equation in the standard form such that it is in vertex form. The first step is to group the linear and quadratic terms, then factor out the coefficient of the quadratic term. After doing so, complete the square, add a value such that the linear and quadratic terms form a perfect square trinomial. Do not forget to balance the equation. The final step is to simplify.

x^2-2x-12=0

Group,

(x^2-2x)-12=0

Complete the square,

(x^2-2x+1)-12-1=0

Simplify,

(x-1)^2-13=0

Now solve the equation using inverse operations,

(x-1)^2-13=0\\\\(x-1)^2=13\\\\x-1=\sqrt{13}\\\\x = \sqrt{13}+1

7 0
3 years ago
Write the function:
kifflom [539]
Notice that our function f(x) is a parabola, and the vertex form of a parabola is:f(x)=a(x-h)^{2} +k where (h,k) are the coordinates of its vertex.
The first thing we need to do is find the vertex (h,k) and to do that we are going to use the vertex formula: h= \frac{-b}{2a}, and then we are going to evaluate our function at h to find k.
We know for our problem that a=-5, and b=-60, so lets replace those values in our vertex formula to find h:
h= \frac{-b}{2a}
h= \frac{-(-60)}{2(-5)}
h= \frac{60}{-10}
h=-6
Now, we are going to evaluate our function at -6 to find k:
k=f(-6)=-5(-6)^{2} -60(-6)-181
k=-180+360-181
k=-1

Now that we have our vertex, where h=-6 and k=-1; lets replace those values in our vertex form equation:
f(x)=-5[x-(-6)]^{2} +(-1)
f(x)=-5(x+6)^{2} -1

We can conclude that the vertex form of our function is f(x)=-5(x+6)^{2} -1, and its vertex is (-6,-1).
7 0
4 years ago
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