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PSYCHO15rus [73]
3 years ago
5

Prove that if b is a square matrix then b+b^t is symmetric

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0
A matrix \mathbf X is symmetric if \mathbf X=\mathbf X^\top. We have

(\mathbf B+\mathbf B^\top)^\top=\mathbf B^\top+(\mathbf B^\top)^\top=\mathbf B^\top+\mathbf B=\mathbf B+\mathbf B^\top

and so \mathbf B+\mathbf B^\top is indeed symmetric.
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Given:

Sample Mean <span>= 30<span>
Sample size </span><span><span><span>= 1000</span></span><span>
</span></span></span>Population Standard deviation or <span><span><span>σ<span>=2</span></span><span>
</span></span>Confidence interval </span><span>= 95%</span>

to compute for the confidence interval

Population Mean or <span>μ<span><span>= sample mean ± (</span>z×<span>SE</span>)</span></span>

<span><span>where:</span></span>

<span><span>SE</span>→</span> Standard Error

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Critical Value of z for 95% confidence interval <span>=1.96</span>

<span>μ<span>=30±<span>(1.96×0.9486)</span></span><span>
</span></span><span>μ<span>=30±1.8594</span></span>

Upper Limit

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Lower Limit

<span>μ <span>= 30 − 1.8594 = <span>28.1406</span></span></span>

<span><span><span>
</span></span></span>

<span><span><span>answer: 28.1406<u<31.8594</span></span></span>

3 0
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