Question

PRECALC HELP NEEDED! Convert the Cartesian equation x^3 = 4 y^2 to a polar equation.

Answer 1

x in (-oo:+oo)

x = (3/4)*y-2 // - (3/4)*y-2

x-((3/4)*y)+2 = 0

x+(-3/4)*y+2 = 0

x-3/4*y+2 = 0 // - 2-3/4*y

x = -(2-3/4*y)

x = -(2-3/4*y)

Hope this helps!