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3 years ago

Enter the phrase as an algebraic expression. p divided by 8 The algebraic expression is

Mathematics

1 answer:

mote1985 [20]3 years ago

4 0

Answer: p/8

Step-by-step explanation: p is being divided by 8, meaning that in a fraction, p would be the numerator and 8 would be the denominator.

I hope this helps, have a good day.

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What is 2 7/8 x 2/3

Vesnalui [34]

Answer:

2.25

Step-by-step explanation:

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3 years ago

What is the value of 7 ^−3 ^ −1 for = −2 and = 4?

andrey2020 [161]

Answer:

d. −7/32

Step-by-step explanation:

The expression that we have to evaluate in this problem is:

$7x^{-3}y^{-1}$

We have to evaluate this expression for:

x = -2

y = 4

We start by rewriting the expression by rewriting it using the following:

$a^{-n}=\frac{1}{a^n}$

So the expression can be rewritten as

$7x^{-3}y^{-1}=\frac{7}{x^3 y}$

Now we observe that:

$(-2)^3=(-2)(-2)(-2)=-8$

Therefore, by substituting x = -2 and y = 4 into the expression, we find:

$\frac{7}{(-2)^3\cdot 4}=\frac{7}{-8\cdot 4}=-\frac{7}{32}$

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3 years ago

2. Frank charges $250 to his MasterCard with an 18% APR. How much will he have to pay at the end of the

Pepsi [2]

Answer:

295

Step-by-step explanation:

250 x ( 1 + APR)

250 x (1 +.18)

250 x ( 1.18)

295

5 0

3 years ago

Ms Rennet buys 500 handbags from the factory at R120 each (excluding VAT).She then sells the handbags to her customers for R 190

Vilka [71]

Answer:

Step-by-step explanation:

3.1.1 What do you mean by SARS

Answer 3.1.2

20% of R190 = R38

38*500=R19000

5 0

3 years ago

The point (2, 1) is a solution to which of the following systems of equations?

Snezhnost [94]

$\huge\boxed{\left \{ {{x+y=3} \atop {3x-y=5}} \right.}$

We can solve this problem by testing the solution against each system of equations. We'll do this by substituting the point into each equation for each system.

<h2>System 1 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}2x+y&=5\\2(2)+1&=5\\4+1&=5\\5&=5\\&\checkmark\end{aligned}&\begin{aligned}-2x+y&=2\\-2(2)+1&=2\\-4+1&=2\\-3&=2\\&\text{X}\end{aligned}\end{array}$

<h2>System 2 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-2x-y&=-5\\-2(2)-1&=-5\\-4-1&=-5\\-5&=-5\\&\checkmark\end{aligned}&\begin{aligned}2x-y&=2\\2(2)-1&=2\\4-1&=2\\3&=2\\&\text{X}\end{aligned}\end{array}$

<h2>System 3 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-x+y&=3\\-2+1&=3\\-1&=3\\&\text{X}\end{aligned}&\begin{aligned}-3x+y&=-5\\-3(2)+1&=-5\\-6+1&=-5\\-5&=-5\\&\checkmark\end{aligned}\end{array}$

<h2>System 4 - $\Large\checkmark$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}x+y&=3\\2+1&=3\\3&=3\\&\checkmark\end{aligned}&\begin{aligned}3x-y&=5\\3(2)-1&=5\\6-1&=5\\5&=5\\&\checkmark\end{aligned}\end{array}$

Since both equations in the final system are true when solved with $(2, 1)$ , the answer is the last system.

3 0

3 years ago