If $150 is shared among 25 people, how much does each person receive?

Pls pls pls pls pls pls answer this need help ASAP

Leokris [45]

Answer: Exponent

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST</em></u></h2>

7 0

3 years ago

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If you mix 1 cup of chocolate chips and 1 cup of raisins what is the percentage of chocolate chips

algol13

Answer:

50%

Step-by-step explanation:

50% because when there is only 2 variables and they are each 1 cup there is an even amount of stuff and when you ask for only one percentage that would be 50% because everything is even. Even if you asked for the percentage for the cup of raisins it would also be 50%. Hope this helps <3

4 0

3 years ago

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

3 years ago

What is the approximate value of the square root of 8 to the nearest tenth?

galina1969 [7]

Square Root to the Nearest Tenth
A B
33 5.7
34 5.8
35 5.9
36 6

3 0

4 years ago

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Find the product of the sum of 57 and 16 and the difference of 61 and 31

Sergio039 [100]

Step-by-step explanation:

???

what is the problem ? you don't know how to add, subtract or multiply yet ?

sum of 57 and 16 : 57 + 16 = 73

difference of 61 and 31 : 61 - 31 = 30

the product of the sum and the difference :

73 × 30 = 2190

3 0

2 years ago