The oil prospector drills wells with a success probability of 0.15. The probability of finding the first productive well in the third attempt is 0.108375 and the probability that the prospector fails to find productive well in the first 5 attempts is 0.26724 or 26.724%
Let Y be the number of drilling trials on which the prospector will find the first productive well. As Y is a geometric random variable with p=0.15 where p is the probability of being successful on any drilling. Let q = 1- p be the probability of being unsuccessful in drilling a well. q = 1 - 0.15 = 0.85
The probability that the first productive well is found on the third attempt is when outcomes are independent
P(Y=3) = q * q * p = 0.85^2* 0.15 = 0.108375
We want to find the probability that 5 wells are drilled and not a productive one is found. That is we need to find p(Y>5). Y is a binomial random variable with several wells drilled at most as n. Given n=5 and p=0.15, q = 0.85
We know the geometric probability is p(y) = p
Then corresponding probabilities are added
p(Y≤ 5 ) = p(0) + p(1) +p(2) + p(3) +p(4) +p(5)= 0.73276
Using the complement rule:
p(Y>5) = 1 - p(Y≤5) = 1- 0.73276 = 0.26724 = 26.724 %
Problem on finding the probability of success on rolling a die:
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Move 3 units from the origin to the left (x-axis) then move 3 units up (y-axis)
Bh/2 = (1/2)bh, so <span>bh/2 and (1/2)bh equivalent expressions</span>
Answer:
B. (-3, -2)
Step-by-step explanation:
Multiply the first equation by -1/3 and add the result to the second equation.
-1/3(3x -3y) +(5x -y) = -1/3(-3) +-13
4x = -12 . . . . simplify
x = -3 . . . . . . divide by 4
Substituting this into -1/3 times the first equation, we get ...
-(-3) +y = 1
y = -2 . . . . . . . subtract 3
The solution is (x, y) = (-3, -2).
Answer:
They are both exactly the same.
Step-by-step explanation: