The formula in order to obtain the vertex form of a
quadratic equation is given as
y=a(x-h)^2+k where (h,k) is the vertex of the quadratic
equation which is parabolic in shape and it is opening upward.
As given in the problem, y=6x^2+12x-10
Using the formula, we can transformed the quadratic equation
y=6x^2+12x-10 into its vertex form:
y=6x^2+12x-10
<span>y= (6x^2+12x)-10 (grouping)</span>
y=6(x^2+2x)-10 (factoring Common terms per
group)
y=6(x^2+2x+1)-10-6 (Completing the squares)
<span>y=6(x+1)^2-16
(Factor and Simplify) </span>
Hence, the vertex form of y=<span>6x^2+12x-10 is y=6(x+1)^2-16</span>
Answer:
μy = $6.56 ; σy = 2.77
Step-by-step explanation:
Given the data :
Mean μx= $8.56
Standard Deviation σx ≈ 2.77
Profit, Y on pizza with current promo :
Price off on pizza = $2
Y = x - 2
μx = E(x) = $8.56
μy = μ(x - 2)
μy = μx - $2
μy = $8.56 - $2
μy = $6.56
For the standard deviation of y
σx ≈ 2.77
σy = σ(x - 2)
σy = σx - 2
Constants are treated as 0 for standard deviation
σy = 2.77
She edits 3 pages in a minute, so it would take her one minute
Step-by-step explanation:
Hi there!
From the question;
The slope of the line is 5/10 or 0.5.
Also the equation of the line passes through the point (0,5).
Note: Use one point formula. {i.e (y-y1)=m(x-x1)}
So, use the formula here and keep the values;
(y-5) = 5/10(x-0)
or, 10(y-5) = 5x
or, 10y-50 = 5x
or, 5x - 10y +50 = 0
Therefore, the required equation is 5x - 10y +50 = 0 or x-2y+10 = 0.
Hope it helps!
Answer:
546
Step-by-step explanation:
