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qaws [65]
3 years ago
10

Plz help me it is very imp for me​ plz I beg you..

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

Answer is derived according to the procedure of calculating LCM of any two numbers

Step-by-step explanation:

If you have any other questions

ask in comments

QveST [7]3 years ago
7 0

\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}

x^2-y^2-1-2y \\\\x^2-(y^2+2y+1)\\\\x^2-(y+1)^2\\\\(x)^2-(y+1)^2\\\\(x+y+1)(x-y-1)

\\\\

y^2-1-x^2-2x\\\\y^2-(x^2+2x+1)\\\\y^2-(x+1)^2\\\\(y)^2-(x+1)^2\\\\(y+x+1)(y-x-1)

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

we have to find the LCM

  • LCM=\sf{(x+y+1)(x-y-1)(y-x-1)   }
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