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Ilya [14]
2 years ago
10

A cookie recipe calls for 3 cups of sugar and yields 24 cookies how much sugar will be needed to make 3 dozen cookies

Mathematics
1 answer:
Sindrei [870]2 years ago
5 0

Answer:4.5 cups of sugar

Step-by-step explanation:

Okay so 24 cookies is 2 dozen

1 cup of sugar would be used for every 8 cookies

3 dozen is equal to 36 cookies

36/8=4.5 so you would need 4.5 cups of sugar

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Solve the system of equations using row operations. Write your answer in the form (x, y).
Sonja [21]

Answer:

(5, - 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = - 2 → (1)

3x - y = 19 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the y- term

9x - 3y = 57 → (3)

Add (1) and (3) term by term to eliminate y

(2x + 9x) + (3y - 3y) = (- 2 + 57), that is

11x = 55 ( divide both sides by 5 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

2(5) + 3y = - 2

10 + 3y = - 2 ( subtract 10 from both sides )

3y = - 12 ( divide both sides by 3 )

y = - 4

Solution is (5, - 4 )

8 0
3 years ago
Tyrone is the supervisor at a water park. His annual salary is $34540. What is his monthly salary?​
icang [17]

Answer:

the answer I got was 2878.3

8 0
2 years ago
Find the measure of one interior angle for the following regular polygon​
givi [52]

Answer:

120

Step-by-step explanation:

All the interior angles in a regular hexagon are 120 degrees.

7 0
3 years ago
Which of these functions is not a linear function? Why?
Nitella [24]

Answer:

f(x)=x3

Step-by-step explanation:

If you meant f(x)=x3 by f(x)=x^3 then that would be a cubic equation and not linear?

5 0
2 years ago
All you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd
Brut [27]

We have the following:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}

replacing:

\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}

6 0
11 months ago
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