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Anna007 [38]
3 years ago
14

A family has two cars. the first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of

35 miles per gallon of gas. during one particular week, the two cars went a combined total of 1525 miles, for a total gas consumption of 40 gallons. how many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
Aliun [14]3 years ago
7 0
Let x and y represent the numbers of gallons used by the 40 mpg and 35 mpg cars, respectively.
.. x +y = 40 . . . . . . . . . . .total consumption is 40 gallons
.. 40x +35y = 1525 . . . . total miles driven = 1525

Multiply the first equation by 40 and subtract the second.
.. 40(x +y) -(40x +35y) = 40(40) -(1525)
.. 5y = 75
.. y = 15
.. x = 40 -15 = 25

The 40 mpg car consumed 25 gallons.
The 35 mpg car consumed 15 gallons.
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Answer:

C = (36/3)* $24

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Step-by-step explanation:

In this question, we are asked to write an equation for cost c of the section of fence needed for the garden and the solve for the value c.

C is already assigned as the cost of the sections she needs for her garden.

We were made to understand that the perimeter of the garden is 36 feet, with a 3 feet each section. Now, what we need to do is to know the number of sections that we have. Since, each section is 3 feet, and the total perimeter is 36 feet, this means that the total number of sections needed would be 36/3. Each of the section as we were told costs $24, so we can then proceed to calculate the value of C from there.

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This is the equation that gives the cost. The actual value of the cost is thus:

C = 12 * 24 = $288

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answer
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