find three consecutive odd integers such that the sum of the middle and largest integer is 21 more than smallest integer.
1 answer:
Answer:
15, 17, 19
Step-by-step explanation:
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Y=radical 3
just cancel out the 2 on both sides
Answer: $2227.41
Step-by-step explanation:
A = P(1 + r/n)^nt
5 × 1. = 5
_ × _. = _
8 × 4. = 32
5/32
Answer:
1. 6/7
2. 1/2
3. 7/10
4. 39/40
5. 15/28
6. 3/10
7. 7/12
8. 1/6
9. 5/12
10. 1/8
Step-by-step explanation:
