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V125BC [204]
3 years ago
7

CAN SOMEONE HELP ME WITH THISSSS

Mathematics
1 answer:
Semmy [17]3 years ago
4 0

Answer:

no i cannot

Step-by-step explanation:

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Espress the following in standard form 24.12<br><br><br>​
ANTONII [103]
Answer: 2412(-2)
(-2)- small numbers

Explanation: you would divide (due to it being a negative 2) by two 10s to get your original number
5 0
3 years ago
If a+2b/a-b =2/3 then b/a=?​
Dominik [7]

Answer:

\frac{b}{a} = - \frac{1}{8}

Step-by-step explanation:

Given

\frac{a+2b}{a-b} = \frac{2}{3} ( cross- multiply )

2(a - b) = 3(a + 2b) ← distribute parenthesis on both sides )

2a - 2b = 3a + 6b ( subtract 3a from both sides )

- a - 2b = 6b ( add 2b to both sides )

- a = 8b ( divide both sides by 8 )

- \frac{1}{8} a = b ( divide both sides by a )

- \frac{1}{8} = \frac{b}{a}

6 0
3 years ago
Read 2 more answers
Kendal ate 27 1/2 cookies in 5 1/2 minutes. How many cookies does she eat per minute?
hjlf

Answer:

5

Step-by-step explanation:

Kendall needs to lay off of the cookies lol

5 0
3 years ago
Read 2 more answers
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
HELP PLEASE ASAP!!!!
topjm [15]

You have to find the angle for it try it!!!!!!!!!!

7 0
3 years ago
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