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Stells [14]
3 years ago
13

scrub-a-Dub toothbrushes are $4,00 each. There is a 10% discount, but there is also a 6% sales tax after the discount is applie

the new price after tax? Round to the nearest penny.
Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0
You multiply the 4.00 by 0.10 to get the 10% discount amount. Then you subtract that from $4.00. Then you multiply that amount by 1.06 to get the total with the 6% sales tax. To get $3.82 rounded to the nearest cent.
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Please help! Need ASAP
pantera1 [17]

Answer:

nobody gonna answer this for 5 points. you have to put 1 question for each 5 points

8 0
4 years ago
· Expand and simplify (x - 2)(x + 7)
lisov135 [29]

Answer:

Expand:

x^2+7x-2x-14

Answer:

x^2+5x-14

Step-by-step explanation:

3 0
3 years ago
In the given figure L1and L2 are two parallel sides . if the area of the rectangle PQRS is 60cm^2 then what is the area of the p
kiruha [24]

Answer:

Step-by-step explanation:

Believe it or not, the two areas are the same.

The base of the rectangle is PQ

The height of the rectangle is PS

Now look at the parallelogram.

The base is PQ

The height is PS

The area has to be the same in both cases. There is no other way to interpret what is happening.

4 0
3 years ago
Precalculus
kodGreya [7K]

Answer:

$24.35

Step-by-step explanation:

We will use the compound interest formula provided to solve this problem:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, change 1% into a decimal:

1% -> \frac{1}{100} -> 0.01

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:

A=800(1+\frac{0.01}{12})^{12(3)}

A=824.35

Lastly, subtract <em>A </em>from the principal to get the interest earned:

824.35 - 800 = 24.35

8 0
3 years ago
In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne
Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0
3 years ago
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