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Setler79 [48]
3 years ago
10

Last one!!!! im so confused

Mathematics
1 answer:
RSB [31]3 years ago
3 0
Answer : 46°

These two angles have the same measure because they are alternate interior angles.
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Which are the roots of the quadratic function f(q) = q2 – 125? Check all that apply.
s344n2d4d5 [400]
F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5
7 0
3 years ago
Read 2 more answers
Write the logarithmic expression as a single logarithm with coefficient , and simplify as much as possible. Assume that all vari
Allushta [10]

Answer:

hope you can understand

4 0
2 years ago
F(x) = 2x + 5
Finger [1]

9514 1404 393

Answer:

  15. f(x) +g(x) = 7x +2

  16. f(x) -g(x) = -3x +8

  17. h(x) · g(x) = 35x -21

Step-by-step explanation:

Substitute the function definition for each function expression and simplify.

__

15. f(x) + g(x) = (2x +5) +(5x -3)

  f(x) +g(x) = 7x +2

__

16. f(x) - g(x) = (2x +5) -(5x -3)

  f(x) -g(x) = -3x +8

__

17. h(x) · g(x) = (7) · (5x -3)

  h(x) · g(x) = 35x -21

4 0
3 years ago
Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
3 years ago
And
kramer

Answer:

can you send a picture please so i can see it?

5 0
3 years ago
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