if the cylinder has a diameter of 4, then its radius is half that, or 2.
![\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=2\\ h=5 \end{cases}\implies SA=2\pi (2)(5+2)\implies SA=4\pi (7) \\\\\\ SA=28\pi \implies SA\approx 87.964594\implies \stackrel{\textit{rounded up}}{SA=88.0}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cylinder%7D%5C%5C%5C%5C%20SA%3D2%5Cpi%20r%28h%2Br%29~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D2%5C%5C%20h%3D5%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D2%5Cpi%20%282%29%285%2B2%29%5Cimplies%20SA%3D4%5Cpi%20%287%29%20%5C%5C%5C%5C%5C%5C%20SA%3D28%5Cpi%20%5Cimplies%20SA%5Capprox%2087.964594%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7BSA%3D88.0%7D)
9514 1404 393
Answer:
the cubic does not exceed the quadratic until x > 8
Step-by-step explanation:
The attached graph plots the two expressions. The two are equal at x=8. Below that value the expression 7x^2 is greater. Above that value, the expression 7x^3 -x^2 is greater.
_____
<em>Comment on the question</em>
The directive to "compare the volumes" does not tell anything about the sort of comparison you are expecting. We note that the expression x^3-x^2 is zero or less up to the point where x=1, so we wonder exactly what it is supposed to be modeling. Any real volume will not be negative.
For small values of x, the quadratic is quite a bit larger. However, we know the cubic will grow larger than any quadratic for large values of x. So, the comparison you get will depend on the domain of interest—which is not specified.
Answer:
207π ft²
Step-by-step explanation:
Given in the question,
diameter of the base = 18 ft
slant height= 14 ft
radius of the base = 18/2
= 9 ft
Formula to calculate the surface area
<h3>A = πrl+πr²</h3>
<em>here l = slant height</em>
<em> r = radius of the base</em>
<em />
plug values in the formula
A = π(9)(14)+π9²
A = 207π ft²
We have a lot of encounters where we are forced to apply our knowledge in geometry, plane figures and especially quadrilaterals. First, we need to know the types of quadrilaterals, it differences, and the corresponding equations. One real world problem is when we are asked to make a kite for our younger sibling and he or she specified the dimensions.
Answer:
The rate of change is 6.
Step-by-step explanation:
Using the point slope form we know that y-y1/x-x1
so 12-6/2-1
this gives 6/1 which is 6.