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3 years ago

Expressing rational numbers with decimal expansions

1 answer:

8 0

Moving the decimal over by counting the 0's and moving over and if u move it past the the last number you add a decimal and put a 0 if there is not enough to numbers always move to the right

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Okay these last two are the last ones i need help on!

icang [17]

21) 5 shelves
22)385mm

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3 years ago

Mrs. JOHNSON paid $40.68 for 3kg of shrimp. What’s the cost of 1 kilogram of shrimp?

Goshia [24]

Answer:

It is 13.56

Step-by-step explanation:

You would have to divide 40.68 by 3. 3 goes 1 time into 4 so it is 10.

4 0

3 years ago

Read 2 more answers

What’s is the solution to the equation x to the power of 2 =16/25

skelet666 [1.2K]

Answer:

$x=\dfrac{4}{5}$

Step-by-step explanation:

The given equation is :

$x^2=\dfrac{16}{25}$

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

$x=\sqrt{\dfrac{16}{25}}$

We know that, 4×4= 16 and 5×5 = 25

So,

$x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}$

So, the solution of the given equation is 4/5.

4 0

3 years ago

Please help and please make sure it’s right

slamgirl [31]

Answer:

135 degrees

Step-by-step explanation:

all the angles in a triangle need to add to 180 degrees, so you take

180-(65+70)= 45

Then you just find the supplementary angle

45+x=180

x=135

7 0

3 years ago

g Given the system of equations: 15 c1 – 5 c2 – c3 = 2400 - 5 c1 + 18 c2 – 6 c3 = 3500 - 4 c1 - c2 + 12 c3 = 4000 (a) Calculate

denpristay [2]

Answer

(a)

$A^{-1} = \frac{1}{3493} \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix}$

(b)

$A^{-1} b = \begin{pmatrix} \frac{500}{7} \\\\ \frac{2400}{7} \\\\ \frac{2700}{7} \end{pmatrix}$

Step-by-step explanation:

Remember that when you want to solve a problem like this, you express the equation as following

$Ax = b$

So, if you know the inverse of $A$ then

$x = A^{-1} b$

For this case

$A = \begin{pmatrix} 15 && 5 && -1 \\ -5 && 18 && -6 \\ -4 && -1 && 12 \end{pmatrix}$

Now for this case the inverse of A would be

$A^{-1} = \frac{1}{3493} \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix}$

Then when you multiply with the vector solution

$A^{-1} b = \frac{1}{3493} \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix} * \begin{pmatrix} 2400 \\ 3500 \\ 4000 \end{pmatrix} = \frac{1}{3493} \begin{pmatrix} 249500 \\ 1197600 \\ 1347300 \end{pmatrix}\\\\\\= \begin{pmatrix} \frac{500}{7} \\\\ \frac{2400}{7} \\\\ \frac{2700}{7} \end{pmatrix}$

So from that information you can conclude that the solution to the system of equations is x = 500/7 y = 2400/7 and z = 2700/7

7 0

3 years ago