Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
I think a fossil? Thats my guess.
Answer: I got you
Explanation: On islands around the globe, invasive European rabbits wreak such havoc on plants and seabirds that governments worldwide have spent a century trying to eradicate the furry beasts. Scientist Scott Pearson had come to this steep uninhabited pile of rocks to catalog the decline of the rhinoceros auklet, a gray seabird that nests deep in hollowed-out hillside burrows. But instead of spying one of the white-eyebrowed creatures, Hodum came eye to eye with the most likely cause of its decline. Rabbits inside the borrow.
They can melt because of global warming.
C: organise into charts ,graphs ,do calculations if necessary.
