9514 1404 393
Answer:
x² +y² -6x -16y +48 = 0
Step-by-step explanation:
<u>Given</u>:
- circle center: (3, 8)
- circle radius: 5
<u>Find</u>:
general form equation for the circle
<u>Solution</u>;
The standard form equation for the circle is ...
(x -h)² +(y -k)² = r² . . . . . circle with radius r centered at (h, k)
(x -3)² +(y -8)² = 5²
Subtracting 25 and expanding this will give the general form.
x² -6x +9 +y² -16y +64 -25 = 0
x² +y² -6x -16y +48 = 0
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<em>Additional comment</em>
"General form" of an equation is usually the form f(x,y) = 0, where f(x, y) is written in "standard form," with terms in lexicographical order and decreasing degree.
