Answer:
a) for all values of x that are in the domains of f and g.
b) for all values of x that are in the domains of f and g.
c) for all values of x that are in the domains of f and g with g(x)≠0
Step-by-step explanation:
a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.
b) By definition (fg)(x)=f(x)g(x). Then x must be in the domain of f and g.
c) By definition (f/g)(x)=f(x)/g(x). Then x must be in the domain of f and g and g(x) must be different of 0.
<em>Answer:</em>
<em>The perfect squares are the squares of the whole numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 and so on.......</em>
Step-by-step explanation:
We see that CF and DE are parallel to each other, which means that they had the same length with each other, so:
6n-1=5n+9
Subtract 5n for both side
6n-1-5n=5n+9-5n
n-1=9
Add 1 for both side
n-1+1=9+1
n=10
CF=
6n-1
=6(10)-1
=60-1
=59
DE=
5n+9
=5(10)+9
=50+9
=59
CD/FE:
4n+2
=4(10)+2
=42
True/False:
n=10 True
n=7 False
CF=59 True
FE=42 True
CD=30 False. As a result, n=10;CF=59; and FE=42 is your final answer. Hope it help!
