Answer:
E. 0.759
Step-by-step explanation:
You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN
The sine of angle ∠LMN is 0.759, find the value of ∠LMN
∠LMN=49.38°
Find angle ∠LNM
You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence
∠LNM=180°-(90°+49.38°)
∠LNM= 180°-139.38°=40.62°
Find cos 40.62°
Cos 40.62°=0.7590
The correct answer is the first one
Answer:
y= -1.5x-7 is the equation of the perpendicular line
Here's why:
when we convert 2x-3y=8 to standard form, we get y= 2/3x-8/3. This means the perpendicular line will have a slope of the negative reciprocal of the original one, so the perpendicular slope is -1.5. When we substitute the points (-2,-4) into the equation y=-1.5x+b, we get a b value of -7. So the perpendicular line equation is y= -1.5x-7. You can't the parallel line equation with the points (-2,-4) as it is part of the line 2x-3y=8.
Answer:
40 / 16 = 2.5
Step-by-step explanation: ur telling me this is highschool math? lol. im in middle school but took this stuff in third grade.
