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NARA [144]
4 years ago
12

A kilobyte is 2^10 bytes and a megabyte is 2^20 . how many kilobytes are in a megabyte

Mathematics
1 answer:
tamaranim1 [39]4 years ago
8 0

Answer:

1024

Step-by-step explanation:

so first you would do 2^10 and 2^20

2^10 = 1024

2^20 = 1048576

then you would just divide 1048576 by 1024

1048576 / 1024 = 1024

You might be interested in
Which point is located at (4, -2)?
larisa86 [58]
Point B is located at point (4, -2)
7 0
3 years ago
Find the area of the following shape.
ad-work [718]

Answer:

57 units^2

Step-by-step explanation:

First find the area of the triangle on the left

ABC

It has a base AC which is  9 units and a height of 3 units

A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5

Then find the area of the triangle on the right

DE

It has a base AC which is  6 units and a height of 1 units

A = 1/2 bh = 1/2 ( 6) *1  = 3

Then find the area of the triangle on the top

It has a base AC which is  3 units and a height of 3 units

A = 1/2 bh = 1/2 ( 3) *3  = 9/2 = 4.5

Then find the area of the rectangular region

A = lw = 6*6 = 36

Add them together

13.5+3+4.5+36 =57 units^2

5 0
3 years ago
Read 2 more answers
A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the w
Fudgin [204]

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

<h3>What is an area?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

                                  = 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

                     = 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

                  = ( π/2 ) r² + (π/2) r² + ( L x W )

                  =  π  r² + (  L x W)

                  = π ( 4 )² + ( 125 x 8 )

                  = 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

To know more about an area follow

brainly.com/question/25292087

#SPJ1

3 0
2 years ago
PLEASE HELP ME WILL MARK AS BRINIEST.
Arisa [49]

Answer:

-14w²-7w+1

Step-by-step explanation:

(–7w2 – 2w – 1) – (–5w2 + 3w – 2)

-14w²-2w-2w-1 +10w²-3w+2

combine the like terms

-14w² + 10w² - 2w-2w-3w+2-1

-4w²-7w+1

4 0
3 years ago
I dont Understand this so can anyone help me please!! Thank you
storchak [24]
Youre correect answer is 70
3 0
3 years ago
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