Answer:
300 seconds
Step-by-step explanation:
The first dog run at v₁ = 15 m/sec the second one run at v₂ = 12 m/sec
we know that d = v*t then t = d/v
Then the first dog will take 300/ 12 = 25 seconds to make a turn
The second will take 300 / 15 = 20 seconds to make a turn
Then the first dog in 12 turns 12*25 will be at the start point, and so will the second one at the turn 15.
To check first dog 12 * 25 = 300
And the second dog 15 * 20 = 300
That means that time required for the two dogs to be at the start point together is
300 seconds, in that time the first dog finished the 12 turns, and the second had ended the 15.
Another procedure to solve this problem is as follows:
between 12 m/sec and 15 m/sec the minimum common multiple is 300 ( 300 is the smaller number that accept 12 and 15 as factors 12*15 = 300) Then when time arrives at 300 seconds the two dogs will be again in the starting point
Answer:
0
Step-by-step explanation:Velocity at t= 0s is 20m/s and the velocity at t= 10s is 20m/s.
a= 20-20/ 10s
a=0m/s
Answer:
100n back i guess
Step-by-step explanation:
rip kids foot
the top is adding 1 and the bottom is subtracting 5
In your question which ask for the statement that best fit in your theorem that a parallel line to one side of a triangle divides the other two porportionately which states that segment DE is parallel to segment BC and segment EF is parallel to AB so the answer is BD=15
