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Ierofanga [76]
3 years ago
7

Someone Please Help.

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Hi there!

\large\boxed{f(-6) = 5}

The value of f(-6) is the y-value at the x-coordinate x = -6.

Looking at the graph, we can see that at x = -6, y = 5.

Therefore, f(-6) = 5.

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A distribution is given as
Nesterboy [21]

Answer:

the answer will be 5.

Step-by-step explanation:

6 0
3 years ago
PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRRR
tekilochka [14]

Answer:

a=11, b=53

Step-by-step explanation:

y=ax+b

x=1, y=64 -> 64=a+b

x=2, y=75 -> 75=2a+b

75-64=a, a=11, b=53

All the other points obey this rule.

8 0
3 years ago
Read 2 more answers
Given f(x) = 4x - 6, evaluate f(3).<br><br> A. 2<br><br> B. 1<br><br> C.12<br><br> D. 6
Dima020 [189]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
One quart of water-resistant paint covers 75 square feet. A swimming pool is in the shape of a rectangular prism with a length o
docker41 [41]

18.66 quarts of paint is needed to paint the swimming pool with two coats of paint

<em><u>Solution:</u></em>

Given that,

<em><u>A swimming pool is in the shape of a rectangular prism</u></em>

Length = 20 feet

Width = 10 feet

Height = 5 feet

<em><u>Find the surface area of prism</u></em>

A=2(wl+hl+hw)

Where, "l" is the length and "w" is the width and "h" is the height

A = 2(10 \times 20 + 5 \times 20 + 5 \times 10)\\\\A = 2(200+100+50)\\\\A = 2 \times 350\\\\A = 700

Thus surface area area of prism is 700 square feet

Given that,

One quart of water-resistant paint covers 75 square feet

Therefore,

1 quart paint = 75 square feet

x quart = 700 square feet

This forms a proportion

1 \times 700 = 75 \times x\\\\x = \frac{700}{75}\\\\x = 9.33

Thus 9.33 quarts of paint is needed to cover 700 square feet

How many quarts should you buy to paint the swimming pool with two coats of paint

For two coats of paint we need = 9.33 + 9.33 = 18.66 quarts of paint

4 0
3 years ago
How is the point (2, 9) in the scatterplot described?
AnnZ [28]
Im not sure but u can search up the name and see online i would help if i could i hope the advise i gave helps just seach up if no one can help im so sorry i wanted to help but idk this stuff yet sorry
7 0
3 years ago
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