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densk [106]
3 years ago
13

I NEED HELP I WILL GIVE BRAINLIEST TO WRITE ANSWER

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
3 0
Y=-2x+11
i think this should be correct!
pshichka [43]3 years ago
3 0

Answer:

y=-2x + 1

Step-by-step explanation:

y=mx+b      (0,1)

11-2=9

9-2=7

7-2=5

5-2=3

3-2=1

You might be interested in
Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.
Vlad [161]

Answer:

Catron's error is

"She did not follow order of operations"

Step-by-step explanation:

Catron evaluates the expression (negative 9) (2 and two-fifths)

That expression can be written as below

(-9)(2\frac{2}{5})

Catron's error is

"She did not follow order of operations"

The corrected steps are

Step1: Given expression is (-9)(2\frac{2}{5})

Step2: Convert mixed fraction into improper fraction

(-9)(2\frac{2}{5})=(-9)(\frac{12}{5})

Step3: Multiplying the terms

(-9)(2\frac{2}{5})=-7\frac{-108}{5}

Therefore solution (-9)(2\frac{2}{5})=-7\frac{-108}{5}

6 0
3 years ago
Read 2 more answers
If there are 12 boys and 60 girls in a room, fill out all of the possible ratios of boys to girls that could be made.
Oksana_A [137]

Answer:

6:30

1:5

4:20

3:15

2:10

Step-by-step explanation:

im pretty sure these are correct

7 0
3 years ago
URGENT URGENT URGENT URGENT! THIS QUESTION GIVES BRAINLIEST FOR FIRST GOOD ANSWER!
Igoryamba

Answer: 2.43m^3

Step-by-step explanation:

6 0
3 years ago
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Solve this the link is down below
kogti [31]
There is no link here
4 0
3 years ago
What is the equation of the midline of the sinusoidal function?<br> [Enter the answer in the box]
Contact [7]

Answer:

y=0

Step-by-step explanation:

We are asked to find the equation of mid-line of the given sinusoidal function.

Since the mid-line of a sinusoidal function is the line that runs between the maximum and minimum y-values of the function. We can consider it the middle y-value.

\text{Mid-line}=\frac{\text{Maximum value+Minimum value}}{2}

We can see from our given graph that the maximum value of our function is 5 and minimum value of our function is -5.

Upon substituting these values in mid-line formula we will get,

\text{Mid-line}=\frac{5+(-5)}{2}

\text{Mid-line}=\frac{5-5}{2}

\text{Mid-line}=\frac{0}{2}

\text{Mid-line}=0

Therefore, the equation of the mid-line of the given sinusoidal function is y=0.

3 0
3 years ago
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