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3 years ago

7

PLZ HELP ASAP!! 16 points!! What are the domain and range of the function graphed below?

1 answer:

Pavlova-9 [17]3 years ago

8 0

Answer:

B. Domain: {-∞ < x < ∞}; Range: {y ≤ 2}

Step-by-step explanation:

In simple terms, the domain of a graphed function refers to all the possible x-values while the range refers to all the possible y-values. Therefore, based on the graph the answer would be.

B. Domain: {-∞ < x < ∞}; Range: {y ≤ 2}

This is because x is in a slope and extends infinitely both to the left and to the right, therefore having all possible values. The y-axis starts at and includes the value 2 and all values less than 2. A black filled in dot in a graph indicates that the value is included.

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sleet_krkn [62]

I had to look for the options and here is my answer:

Based on the description of the behavior that Ron has exhibited, this explains that his behavior is based on intrinsically motivated behavior. Intrinsic means inherent or inborn. The behavior he possesses are already natural to him and are not acquired.

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4 years ago

If Madison had 10 apple and gave 3 away to Zack how many apples does she have

Ulleksa [173]

Answer:

7 i think because 10-3 =7

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Step-by-step explanation:

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2 years ago

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Pre-Calculus - Systems of Equations with 3 Variables please show work/steps

inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

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3 years ago

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Vlada [557]

Your sentence is not complete. Please proofread your questions before sharing them.

I think you meant:

"<span>Buses on your route run every 11 minutes from 7 AM to 11 AM. YOU arrive at the bus stop at 8:18 AM how long will you HAVE TO wait for a bus?"

Let's try this:

First bus arrives at 7 a.m. The next one arrives at 7:11, the next at 7:22, the next at 7:33, the next at 7:44, the next at 7:55, the next at 8:06, the next at 8:17, and the next at 8:28. You'll have to wait 10 minutes for the 8:28 bus.</span>

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4 years ago

Explain why numbers with a 5 in the ones place are not prime numbers.

Pepsi [2]

Because it's divisible by 5 even though 5 is a prime number

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3 years ago

Read 2 more answers