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OLEGan [10]
2 years ago
7

PLZ HELP ASAP!! 16 points!! What are the domain and range of the function graphed below?

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
8 0

Answer:

B. Domain: {-∞ < x < ∞}; Range: {y ≤ 2}

Step-by-step explanation:

In simple terms, the domain of a graphed function refers to all the possible x-values while the range refers to all the possible y-values. Therefore, based on the graph the answer would be.

B. Domain: {-∞ < x < ∞}; Range: {y ≤ 2}

This is because x is in a slope and extends infinitely both to the left and to the right, therefore having all possible values. The y-axis starts at and includes the value 2 and all values less than 2. A black filled in dot in a graph indicates that the value is included.

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Need answer Immediately!!!!!!
slamgirl [31]

Answer:

I believe it is 48%

Step-by-step explanation:

The total amount of people who liked to read printed books is 67.

Then the total amount of people who liked either print or electronic books is 140.

If I am remembering correctly, you would divide 67 by 140 to get the percentage of people who like to read printed books.

<u>67/140 = 48%</u> (rounded)

4 0
3 years ago
What is the radius and diameter of each circle ?
Oxana [17]

Answer:

A

radius is 11

diameter is 22

B

radius is 15

diameter is 30

C

radius is 13

diameter is 26

D

radius is 7

diameter is 14

7 0
2 years ago
Read 2 more answers
Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
g A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam. We ar
BaLLatris [955]

Answer:

The test statistic is z = 1.25

Step-by-step explanation:

We are interested in determining whether or not the proportion of the student who experience anxiety during the exam is significantly more than 80%.

At the null hypothesis, we test if the proportion is 80%, that is:

H_0: p = 0.8

At the alternate hypothesis, we test if the proportion is more than 80%, that is:

H_a: p > 0.8

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

80% is tested at the null hypothesis:

This means that \mu = 0.8, \sigma = \sqrt{0.2*0.8} = 0.4

A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam.

This means that n = 100, X = \frac{85}{100} = 0.85

The test statistic is

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.85 - 0.8}{\frac{0.4}{\sqrt{10}}}

z = 1.25

The test statistic is z = 1.25

4 0
3 years ago
Evaluate the function for f(3).<br> f(x) = -3x - 8
scoundrel [369]
If 3 is x that means y is -17 so that mean f=-17/3
8 0
3 years ago
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