Slope 1/7 ; easiest way to remember is rise over run
<h3>Answer: 0.47178 Step-by-step explanation:
Find the probability for each p(X=x) up to 5 using the equation: (x-1)C(r-1)*p^r * q^x-r,
where x is number of days, p = .3 (prob of rain). q=.7 (prob of not rain), and r=2 (second day of rain). also C means choose.
So p(X=1) = 0
p(X=2) = 1C1 * .3^2 * .7^0 = .09
P(X=3) = 2C1 * .3^2 * .7^1 = .126
P(X=4) = 3C1 * .3^2 * .7^2 = .1323
P(X=5) = 4C1 * .3^2 * .7^3 = .12348
Then add all of them up
0+.09+.126+.1323+.12348 = .47178</h3>
Answer:
Equation of tangent plane to given parametric equation is:

Step-by-step explanation:
Given equation
---(1)
Normal vector tangent to plane is:


Normal vector tangent to plane is given by:
![r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]](https://tex.z-dn.net/?f=r_%7Bu%7D%20%5Ctimes%20r_%7Bv%7D%20%3Ddet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5Ccos%28v%29%26sin%28v%29%260%5C%5C-usin%28v%29%26ucos%28v%29%261%5Cend%7Barray%7D%5Cright%5D)
Expanding with first row

at u=5, v =π/3
---(2)
at u=5, v =π/3 (1) becomes,



From above eq coordinates of r₀ can be found as:

From (2) coordinates of normal vector can be found as
Equation of tangent line can be found as:

Answer:
300$
Step-by-step explanation:
divide 120 by 4 and then mutiply the answer on that by 10
Answer:
Step-by-step explanation:
2x² - 7x - 3 = 1
Step 1: 2x² - 7x - 4 = 0
Step 2: incorrect.
Use Quadratic Formula to solve for roots.
x = [7 ± √(7² – 4·2(-4))] / [2·2]
= [7 ± √81] / 4
= [7 ± 9] /4
= -0.5, 4