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Ede4ka [16]
3 years ago
5

Bad Investment After Mrs. Fisher lost 9% of her investment, she had $22,750. What was Mrs. Fisher's original investment?​

Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

$2500

Step-by-step explanation:

Given that,

The lost percentage = 9%

Amount she had = $22,750

We need to find Mrs. Fisher's original investment.

As she had lost 9%, it means she will remain with 91% of her investment. Let the original investment is x.

So,

91\%\ of \ x=22,750\\\\\dfrac{91}{100}x=22,750\\\\x=\dfrac{22,750\times 100}{91}\\\\x=\$25000

So, her original investment is equal to $25000.

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miss Akunina [59]

It's gonna be 0.5/10

7 0
3 years ago
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PLEASE HELP, GIVING 55 POINTS IF YOU ANSWER (08.03/08.05 MC) A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: E
Andrew [12]

Answer:

  A. (1, -2)

  B. the lines intersect at the solution point: (1, -2).

Step-by-step explanation:

A. The equations can be solve by substitution by using the y-expression provided by one of them to substitute for y in the other.

This gives ...

  3x -5 = 6x -8

Adding 8-3x to both sides, we get ...

  3 = 3x

Dividing both sides by 3 gives ...

  1 = x

Substituting this value into the first equation, we can find y:

  y = 3(1) -5 = -2

The solution is (x, y) = (1, -2).

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B. The lines intersect at the solution point, the point that satisfies both equations simultaneously. That point is (1, -2).

8 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
Please help me with this question. Thank you!
mr_godi [17]

A-1,6

B-(-1,-5)

c-(-8,2)

D.4,-9

E.3,8

7 0
3 years ago
Which one is it? Help
saul85 [17]

The answer would be letter B.

5 0
3 years ago
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