Answer:
the answer to your question is 807
Step-by-step explanation:
have a nice day
Answer:
54
Step-by-step explanation:
9 x 3 = 27
27 + 27 = 54
-16t^2 + v0t + h0
= -16(t^2 - 1/16 v0t) + h0
= -16 [(t - 1/32v0)^2 - (1/32 v0)^2 ) + h0
= -16(t - 1/32v0)^2 + 1/64 (v0)^2 + h0 which is the vertex form
The vertex is at the point (1/32v0, 1/64 (v0)^2)
1/32v0 represents the time when the firework is at its maximum height and 1/64 (v0)^2 is this maximum height
Answer:
The value will be used as the point estimate for the mean endowment of all private colleges in the United States is of 180.975 millions of dollars.
Step-by-step explanation:
When we have a sample, the mean of the sample is used as the point estimate for the mean of the entire population.
What value will be used as the point estimate for the mean endowment of all private colleges in the United States?
We have to find the mean of the 8 colleges. So

The value will be used as the point estimate for the mean endowment of all private colleges in the United States is of 180.975 millions of dollars.
Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Step-by-step explanation:
<em>Explanation</em>:-
<em>Given sample size 'n' =10</em>
<em>mean of the Population = 90 words per minute</em>
<em>standard deviation of the Population =10 wpm </em>
<em>we will use formula</em>
<em> </em>
<em></em>
<em>Let X⁻ = 96</em>

Z = 1.898
<em>The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute</em>
<em></em>
<em></em>
<em> = 1- P( Z ≤z⁻)</em>
<em> = 1- P(Z<1.898)</em>
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
<u><em>Final answer</em></u>:-
The probability that a random sample of 10 second grade students from
= 0.0359