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2 years ago

I need help with this problem

Mathematics

1 answer:

alexandr402 [8]2 years ago

7 0

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4

Finally, this should be re-written as

4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30 4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

2x^2y^8 1

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igomit [66]

ANSWER

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iren2701 [21]

Answer:

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<h3>How to find the statement that is true about the functions a(x) = b(x) at x = 2?</h3>

If we have two functions a(x) and b(x), a statement is made that a(x) = b(x) at x = a, this implies that the values of the functions a(x) and b(x) are equal at x = a.

Given that the two functions a(x) and b(x), a statement is made that a(x) = b(x) at x = 2.

Then the statement that is definitely true about x = 2 is Both a(x) and b(x) have the same output value at x = 2.

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