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lara31 [8.8K]
3 years ago
15

I need help with this problem

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as:  (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2.  Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4:  4y^2*x^4*y^20.  This is followed by the product of y^2 and y^20:                   4*y^22*x^4

Finally, this should be re-written as

                                    4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30      4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

  2x^2y^8                  1

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Step-by-step explanation:

Angles a and b add to 180° (linear pair), so angle b is 68°.

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PLEASE HELP DUE TODAY!! GIVING BRAINLIEST, REPORTING BITLY ANSWERS
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Answer:

Minimum: 50

Lower Quartile:  59

Median:  66

Upper Quartile: 74

Maximum: 92

Step-by-step explanation:

50, 55, 58, 60, 62, 64, 68, 70, 72, 76, 84, 92

Minimum: 50

Lower Quartile: (58 + 60)/2 = 59

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Upper Quartile: (72 + 76)/2 = 74

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2 years ago
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Step-by-step explanation:

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motikmotik

Answer:

Step-by-step explanation:

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Make 2.5--->2.500

Subtract: 2.500

                1.125

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Step-by-step explanation:

If we have two coordinates on a line (x1,y1 =1,2) and (x2, y2 =3,6) we can solve for m as follows. (x2,y2) 6=m3+c - (x1,y1) 2=m1+c

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