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postnew [5]
3 years ago
12

GRADE 7 MATH URGENT

Mathematics
2 answers:
crimeas [40]3 years ago
8 0

A. 8 pizza pies at 10 pc. per pie = 80 available pieces

B. Let X be the number of children. Number of pieces eaten = 5 per child = 5X.

c. 22 pieces are left over.

D. Combine line A and line C. Total number of pieces eaten = 80 original minus 22 left over. Result 58 pieces were eaten by X children: 58 = 5X.

E. Solve the equation 58 = 5X by dividing both sides by 5.

WHOOPS! Is this a trick question? Solving the above results in the answer that there are 11.6 children at the party. Hmmm. That 0.6 child is a question mark for me.

Looks like someone miscounted the pizza slices. Or omitted some pertinent information. But, I’m sure there is a logical answer.

WITCHER [35]3 years ago
7 0

Answer:

10 pizzas

Step-by-step explanation:

To find the answer for this question you need to multiply 3/8 by 25.

3/8 * 25 = 9.375

You can't buy .375 of a pizza so you round it up and get 10.

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A movie theater has a seating capacity of 315. The theater charges $5 for children, $7 for students, and $12 of adults. There ar
xxTIMURxx [149]

Answer:

that the answer let me know if i am wrong hope this helps

Step-by-step explanation:

ANSWER.  77 adults;  2*77 = 154 children and the rest (315-77-154) = 84 students.

4 0
2 years ago
Lowest common multiple of of 3,5,6
pogonyaev

Answer:

30

hope it helps........

4 0
3 years ago
Read 2 more answers
Find the distance between (5, -1) and<br> (-3,0).<br> Give your answer correct to 1 decimal
tankabanditka [31]

√65Explanation:(−5,1)=x1,y1(3,0)=x2,y2The distance is calculated using formula:'Distance =√(x2−x1)2+(y2−y1)2=√(3−(−5))2+(0−1)2=√(3+5)2+(−1)2=√(8)2+(−1)2=√(64+1)Distance =√65

3 0
2 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

7 0
4 years ago
What is the index of ⁴√81<br>​
ludmilkaskok [199]

Answer:

8

HOPING MAKATULONG PO!,KEEP SMILLING GOD LOVES YOU:)!

3 0
3 years ago
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