Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
This would be 3x + y = 0.
I hope this helps!
Answer:
7b+5
Step-by-step explanation:
10b + 7 − 3b −2
=10b + 7 + −3b + −2
Combine Like Terms:
=10b + <u>7 </u>+ −3b + <u>−2
</u>
=(10b + −3b) + ( <u>7 </u>+ <u>−2</u>)
=7b + <u>5</u>
Answer:
7b + 5
Hope this helps : )
