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3 years ago

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[PLEASE HELP] Each of these statements describe a transformation of a graph of y = x, The which of the statements correctly desc

ribe the graph of y =x + 7???

2 answers:

aev [14]3 years ago

7 0

Answer:

The answer is B

Step-by-step explanation:

well the equation of a line is : y = mx + b

in this question the equation is y = x

so the line y = x +7 will be 7 units up than y = x

Sphinxa [80]3 years ago

5 0

Answer:

B

Step-by-step explanation:

Adding the 7 to the input (x) will increase the output (y) by 7. Therefore, the graph is translated 7 units up.

You might be interested in

true or false: the points (6, 13), and (21, 33) and (99, 137) all lie on the same line. th equation of the lines is y + /3x + 5.

Phoenix [80]

Answer:

point A (6,13) lies on the equation. True

given point B(21,33) lies on the equation. True

given point C (99, 137) lies on the equation. True

The equation that was given was y = 4/3x + 5

Now,check the given equation for the given points.

1) A (6,13)

Substitute x = 6 in the given equation y = 4/3x +5

y = 4/3(6) + 5 = 4(2) + 5 = 8+5 = 13

y=13

the given point A (6,13) lies on the equation.

2) B (21,33)

Substitute x = 21 in the given equation y=4/3x+5

y=4/3(21) + 5 = 4(7) + 5=28+5=33

y = 33

the given point B(21,33) lies on the equation.

3) C (99, 137)

Substitute x = 99 in the given equation y = 4/3x + 5

y=4/3(99) + 5 = 4(33) + 5 = 132 + 5 = 137

y = 137

the given point C (99, 137) lies on the equation.

There is your answer

8 0

2 years ago

If a1=4 and an =2an-1 – 1 then find the value of a4.

musickatia [10]

1 = 4

a2 = -2(a1) - 1
a2 = -2(4) - 1
a2 = -9

a3 = -2(a2) - 1
a3 = -2(9) - 1
a3 = -19

Can you do a4 and a5 and answer?

7 0

2 years ago

Help ASAP!!!!!!!!!!!!!!!

Advocard [28]

Answers D. and E. are correct.
I think that B might also be correct, I hope This helps.

7 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

A box is filled with 6 blue cards, 6 brown cards, and 3 green cards. A card is chosen at random from the box. What is the probab

Luden [163]

Answer:

60% chance of a blue or green card

6 0

2 years ago