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marishachu [46]
3 years ago
8

Find the domain and range.

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

Domain: -5 < x ≤ 1

Range: -3 ≤ y ≤ 1

Step-by-step explanation:

For domain, the point on the most left is an open circle, meaning it is a greater than sign. The values of x is greater than -5 and less than or equal to 1.

For range, the lowest point is at -3, and the highest is at 1. Therefore, the range is greater than or equal to -3 and less than or equal to 1.

Advocard [28]3 years ago
4 0

Answer:

Domain: -5 < x ≤ 1

Range: -3 ≤ y ≤ 1

help me by marking as brainliest....

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3 0
3 years ago
1/3 and 3/5 as a decimal
DedPeter [7]
0.33333333 ( repeating )
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8 0
3 years ago
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Prove it. this question is from trigonometry ​
konstantin123 [22]

Answer:

See below for step-by-step proof.

Step-by-step explanation:

\textsf{Given expression}:

\cos^6 \theta+\sin^6 \theta

\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c:

\implies (\cos^2 \theta)^3+(\sin^2 \theta)^3

\textsf{Use the identity}\quad a^3+b^3=(a+b)^3-3ab(a+b):

\implies (\cos^2 \theta+\sin^2 \theta)^3-3 \cos^2 \theta\sin^2 \theta (\cos^2 \theta+\sin^2 \theta)

\textsf{Use the identity}\quad \sin^2 \theta + \cos^2 \theta=1:

\implies (1)^3-3 \cos^2 \theta\sin^2 \theta (1)

\implies 1-3 \cos^2 \theta\sin^2 \theta

\implies 1-3 (\cos \theta\sin \theta)^2

\textsf{Use the identity}\quad \sin 2 \theta=2 \sin \theta \cos \theta \implies \dfrac{1}{2}\sin 2 \theta= \sin \theta \cos \theta:

\implies 1-3 \left( \dfrac{1}{2}\sin 2 \theta\right)^2

\implies 1-\dfrac{3}{4} \sin^2 2 \theta

\textsf{Use the identity}\quad \sin^2 2\theta + \cos^2 2\theta=1 \implies \sin^2 2\theta=1-\cos^2 2\theta

\implies 1-\dfrac{3}{4} \left(1-\cos^2 2 \theta\right)

\implies 1-\dfrac{3}{4} +\dfrac{3}{4}\cos^2 2 \theta

\implies \dfrac{1}{4} +\dfrac{3}{4}\cos^2 2 \theta

\textsf{Factor out }\dfrac{1}{4}:

\implies \dfrac{1}{4}\left(1+3\cos^2 2 \theta\right)

\textsf{Use the identity}\quad \cos (4 \theta)=2 \cos^2 2\theta - 1 \implies \cos^2 2 \theta=\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}:

\implies \dfrac{1}{4}\left(1+3\left(\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}\right)\right)

\implies \dfrac{1}{4}\left(1+\dfrac{3}{2}\cos 4 \theta+\dfrac{3}{2}\right)

\implies \dfrac{1}{4}\left(\dfrac{5}{2}+\dfrac{3}{2}\cos 4 \theta\right)

\implies \dfrac{1}{4} \cdot \dfrac{1}{2}\left(5+3\cos 4 \theta\right)

\implies \dfrac{1}{8}\left(5+3\cos 4 \theta\right)

6 0
2 years ago
Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels?
NeX [460]
Answer: $3.30

Explanation: 
You set up a proportion where 

9.25      X
------ = -----
2.8        1

Then you cross multiply and see that...
2.8X = 9.25
Then X = 9.25 / 2.8 = 3.30

4 0
3 years ago
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How can I answer this question?
stiv31 [10]
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7 0
4 years ago
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