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Anestetic [448]
3 years ago
9

PLS PLS HELP ME PLS

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer:

All I see is white need to post another

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Your class earned $110.00 Saturday afternoon by washing cars to raise money for a class trip. This is 14 of the money needed for
I am Lyosha [343]

Answer

D. 440

Step-by-step explanation:

you had me confused so I had to go in my mathmetics book it was 1/4 not 14 thats what had me confused

4 0
3 years ago
Find the equation of the line that passes through the point and is perpendicular to the line 3d
professor190 [17]
This on is very easy go to my website so i can explain it better for you

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7 0
3 years ago
Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
Find the distance between theses points:(8,0),(-6,6). Round answer to nearest tenth if necessary.
11111nata11111 [884]

Answer:

Chicken strips

Step-by-step explanation:

Dont ask they are just on my mind

7 0
3 years ago
The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
Hunter-Best [27]

Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

\boxed{A)\ (-5,7)}

8 0
3 years ago
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