2 years ago

Find the measure of angle 1 and 2 pls

Mathematics

1 answer:

Flura [38]2 years ago

4 0

Answer:

Your answer is

1. 42.5

2. 95

Hope that this is helpful. Vote and like it

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2 years ago

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

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6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

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∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

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2 years ago

Find the measure of angle 1 and 2 pls​

Find the measure of angle 1 and 2 pls