Answer:
def func1(x, y, z):
return z*3*y - x
x= int(input("Enter x"))
y= int(input("Enter y"))
z= int(input("Enterz"))
solveEquation=func1(x, y, z)
print (solveEquation)
Explanation:
Please check the answer section.
<span>If you were optimizing for performance
and wanted to support potentially adding many new elements to an adt, then a
list would allow faster addition of elements than an array. The object that
contains the data of similar type is called an array. When the array is
created, its length of array is established.</span>
A looping is a set of instructions which is repeated a certain number of times until a condition is met. hlo dai k xa halkhabar
Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
Answer:
low transaction fees and speedier processing
Explanation: