Write a one register parameter procedure that converts an ASCII digit in AL to its corresponding binary value. If AL already con
1 answer:
Using the parameter to convert a digital ASCII code into AL we have that it will be necessary to recognize this code and the input values, in this way:
<h3>Writing this code, we have:</h3><em>data segment</em>
<em>”ENTER ANY VALUE”</em>
<em>start:</em>
<em>movah,9</em>
<em>int21h</em>
<em>movah,4ch</em>
<em>int21h</em>
<em>movah,1</em>
<em>subal,30h</em>
<em>endstart</em>
In this case the values that must be put in this code are:
- enter any ASCII value will be 5
See more about ASCII at brainly.com/question/17147612
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Answer:
following are the program to the given question:
Program:
x = 0#defining an integer variable that holds a value
if x < 0:#defining if that checks x less than 0
print("This number ", x, " is negative.")#print value with the message
else:#defining else block
if x > 0:#defining if that checks x value greater than 0
print(x, " is positive")#print value with message
else:#defining else block
print(x, " is 0")#print value with message
if x < 0:#defining another if that checks x less than 0
print("This number ", x, " is negative.")
elif (x > 0):#defining elif block that check x value greater than 0
print(x, " is positive")#print value with message
else:#defining else block
print(x, " is 0")#print value with message
Output:
Please find the attachment file.
Explanation:
In this code, an x variable is defined which holds a value that is "0", in the next step nested conditional statement has used that checks the x variable value and uses the print method that compares the value and prints its value with the message.
In another conditional statement, it uses if that checks x value less than 0 and print value with the negative message.
In the elif block, it checks x value that is greater than 0 and prints the value with the positive message, and in the else block it will print the message that is 0.
