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kirza4 [7]
3 years ago
13

3. State whether the given statements are true or false. a. The computer is called a data processor because it can store, proces

s, and retrieve data whenever needed. b. Modern processors run so fast in term of megahertz (MHz). c. If millions of calculations are to be performed, a computer will perform every calculation with the same accuracy. d. It is very safe to store data and information on the computer independently. e. If some electrical or electronic damages occur, there are no any chances of data loss or damage f. The output devices of the computer like monitor, printer, speaker, etc. can store meaningful information, g. The input devices can display the output after processing. h. Students can also use computer as their learning tools.​
Computers and Technology
1 answer:
andriy [413]3 years ago
6 0

Answer:

a,b,c,d,f,g are true only e is false

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In 1981, the term 4GL was actually used to refer to languages which were <em>non-procedural. </em>A procedural language does not possess <em>object-oriented </em>capabilities. 4GL's often times have OOP properties, so I believe the answer to this question is going to be <em>false. </em>=)
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Give a big-O estimate for the number additions used in this segment of an algorithm.
rjkz [21]
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed. 

(I'm assuming that := is a typo and you mean just =, by the way) 

In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.

This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.

HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES. 
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2). 

(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.

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3 0
3 years ago
What is the decimal format of the binary IP address 11001110.00111010.10101010.01000011?
Neporo4naja [7]

Answer:

206.58.170.67 is the decimal format of the given binary IP address.

Explanation:

we can convert the binary number into decimal by the following procedure.

11001110 = 1x2⁷+1x2⁶+0x2⁵+0x2⁴+1x2³+1x2²+1x2¹+0x2⁰

            = 128 + 64 + 0 + 0 + 8 + 4 + 2 + 0

            =   206

00111010 = 0x2⁷+0x2⁶+1x2⁵+ 1x2⁴+1x2³+0x2²+1x2¹+0x2⁰

               = 0 + 0 + 32 + 16 + 8 + 0 + 2 + 0

               = 58

10101010 = 1x2⁷+0x2⁶+1x2⁵+ 0x2⁴+1x2³+0x2²+1x2¹+0x2⁰

              = 128 + 0 + 32 + 0 + 8 + 0 + 2 + 0

              = 170

01000011 =  0x2⁷+ 1x2⁶+ 0x2⁵+ 0x2⁴+ 0x2³+0x2²+1x2¹+1x2⁰

                = 0 + 64 + 0 + 0 + 0 + 0 + 2 + 1

                =  67

so, the IP address is becomes 206.58.170.67

7 0
3 years ago
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